2. In Labrador dogs, there are 2 loci that determine coat color. The first locus, B is dominant to b. At least one B allele will produce black coat color, while the bb genotype produces a chocolate coat color. This first locus also determines nose color in Labradors: B_ black noses, and bb brown noses. The second locus has a genotype, ee, that is epistatic in nature. Any Labrador with an ee genotype will be yellow. A genotype containing at least one E allele will not affect coat color in Labradors.
You own a male, black Labrador that has been mated to three females producing the following progeny:
Litter Female color Pups
1 Black 10 all black pups
2 Brown 10 all black pups
3 Yellow (brown nose) 5 black pups, & 5 yellow pups with black noses
a) What is the sire’s genotype?
b) What is the probable genotype for the brown female (the mother of litter 2)?
c) What phenotypic ratio is expected if a black male and a yellow female from litter 3 were to be mated? (show work)
black labrador mated to three females, progenies from the third female includes yellow pups with black noses the black male parent is heterozygous at the E locus, otherwise, it cannot have progenies with ee genotype and progenies from female 1 and 2 are all black, and with the third female there are black pups and yellow pups with black nose, so the black parent has to homozygous at the B locus so that all progenies will have B allele.
a) genotype of the black male is BBEe.
b) brown female, has all black pups so her genotype is bbEE.
BBEe * bbEE
| BE | Be | |
| bE | BbEE (black) | BbEe ( Black) |
c) black male * yellow female from litter 3
the yellow pups from the litter 3 has a black nose, this shows the presence of B allele and their yellow mother has a brown nose so they are heterozygous at the B locus, their genotype is Bbee, the black pups have both B and E allele so their genotype is BbEe
BbEe * Bbee
| BE | Be | bE | be | |
| Be | BBEe (black) | BBee (yellow) | BbEe (black) | Bbee (yellow) |
| be | BbEe (black) | Bbee(yellow) | bbEe (brown) | bbee(yellow) |
the phenotypic ratio is
black: yellow:brown=3:4:1
2. In Labrador dogs, there are 2 loci that determine coat color. The first locus, B...
/ fn Labrador retrie brown coat color however, the E gene controls expression of the B gene. The B and E genes interact to yield 3 phenotypes: black (B_E), chocolate (bbE) and yellow ee). What is the phenotypic ratio of the pups that might result vers, the B allele confers black coat color and the b allele from a cross between a yellow female (Bbeo and a chocolate male (hb Be) Coat color in Labrador retrievers is an example of...
the answer I gave was wrong
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2. A recessive allele (e) is epistatic over the B gene locus, producing a golden cot homozygous (ee). Dogs that are homozygous dominant (EE) o determined by the B locus, either black (BB or Bb) or chocolate (bb). Answer the following qs regarding a cross a Labrador retriever with the genotype Bb Ee and a Labrador retriever with the genotype Bb ee r heterozygous (Ee) will show the color A) What is the phenotype of dog 1? B) What is...
Laborador coat color is determined by two genes. The product of gene E determines whether or not pigment is deposited in the fur (Genotype E_ results in pigment deposition, Genotype ee results in no pigment deposition or yellow color). The product of gene B determines whether or that pigment is black or brown (Genotype B_ results in a black pigment, Genotype bb results in a brown pigment). A breeder sets up a cross between a yellow lab [genotype Bbee] and...
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