Using the formula PV = nRT and the following given information:
P = 0.520 atm (H2)
V = 30.0 mL
R = 0.69
T = 22.1 degrees Celsius
find the number of Hydrogen moles produced
Given:
P = 0.52 atm
V = 30.0 mL
= (30.0/1000) L
= 0.03 L
T = 22.1 oC
= (22.1+273) K
= 295.1 K
find number of moles using:
P * V = n*R*T
0.52 atm * 0.03 L = n * 0.08206 atm.L/mol.K * 295.1 K
n = 6.442*10^-4 mol
Answer: 6.44*10^-4 mol
To find the number of moles of hydrogen gas produced, we can rearrange the ideal gas law equation (PV = nRT) to solve for n (number of moles):
n = PV / RT
Given: P = 0.520 atm V = 30.0 mL = 0.0300 L (convert mL to L) R = 0.69 L·atm/(mol·K) T = 22.1 °C = 295.25 K (convert Celsius to Kelvin)
Substituting the values into the equation:
n = (0.520 atm * 0.0300 L) / (0.69 L·atm/(mol·K) * 295.25 K)
n ≈ 0.0079 moles
Therefore, approximately 0.0079 moles of hydrogen gas would be produced.
Using the formula PV = nRT and the following given information: P = 0.520 atm (H2)...
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I have most of it figured out already. My work is in the boxes
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Using the Ideal Gas Law (PV = nRT), calculate the grams of
O2 produced in the reaction. (Hint:
solve for n, and then convert moles to grams. Don’t forget to
convert your temperature from Celsius to Kelvin.) Show your
work.
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