The carboxylic acid group (COOH) in the side chain of Aspartic acid (shown below), one of the 20 naturally occurring amino acids, has a pKa of 4.1. Calculate the percentage of conjugate base (COO- ) for this carboxylic acid group in the side chain of Aspartate at the following pH values: 2.1 , 4.1 and 5.1.
The carboxylic acid group (COOH) in the side chain of Aspartic acid (shown below), one of...
the two carboxylic acid groups of aspartic acid have different acidities with pKa values of 2.1 and 3.9. Predict which acid group is the more acidic by considering the effect of the -nh3+ group on the stability of the conjugate bases. Explain your reasoning.
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Consider a 0.211 L solution of the amino acid aspartic acid (0.631 M), which has an alpha carboxylic acid group (pka = 2.10), an alpha amine group (pka = 9.82), and a carboxylic acid group in the side chain (pka = 3.86). If the titration is started at a very low pH, how many liters of 2.25 M NaOH would you need to add to reach the isoelectric point of the amino acid? Give your answer...
Consider a protein with the acidic side chains, Amino Acid side-chain Arginine pKa = 12.48 Aspartic Acid PKa = 3.90 Cysteine pKa = 8.33 Glutamic acid pKa = 4.07 Histidine pKa = 6.04 Lysine pKa =10.79 Tyrosine pKa =10.13 Given that the pH of blood is about 7.3, how many of the above side chains would be mostly in their ionic form (A-) in blood? 2 3 4 5
Consider a 0.203 L solution of the amino acid aspartic acid (0.615 M), which has an alpha carboxylic acid group (pka = 2.10), an alpha amine group (pka = 9.82), and a carboxylic acid group in the side chain (pka = 3.86). If the titration is started at a very low pH, how many liters of 2.15 M NaOH would you need to add to reach the isoelectric point of the amino acid? Give your answer to 3 significant figures...
1. An amino acid is shown below. Draw a circle around the carboxylic acid group, a square around the side chain and a triangle around the amino group. Finally, put an asterisk next to the C-carbon. HC=0 -C-C-H HNH3+ 2. Consider the molecule below (C&H BINO). After downloading Imol and the molecule files to your computer, measure the values of the indicated bond and torsional angles. CCN HOC = HO 1 OCCC - OCCBr =
Question 2 1 pts Amino acids are classified by their Rgroup (side chain) carboxylic acid group peptide bond alpha carbon amine group
1A solution of 0.235 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.118 M NaOH . The p K a values for aspartic acid are 1.990 , 3.900 , and 10.002 , corresponding to the α-carboxylic acid group, the β-carboxylic acid group, and the amino group, respectively. Calculate the pH at the first equivalence point of this titration.
1. (a) Draw a zwitterionic amino acid with a side chain, R. (b) What are the angles between the Ca bonds? (c) If this is a naturally occurring amino acid, which isomer is it, D or L? (d) Assuming the side chain has no ionizable group, at approximately what pH will the majority of this free amino acid have a net positive charge? A net negative charge?
The one-letter sequence is: WATER
a) Draw the peptide (R-groups trans), indicating charges, in
predominant form found at pH = 0.
b) What is the isoelectric point?
c) What is the average charge on the population of peptide
macromolecules at pH = 2.2?
d) What is the average charge on the population of peptide
macromolecules at pH = 12.5?
TABLE 4.1 Amino Acid Alanine Arginine Asparagine Aspartic acid Cysteine....« Glutamic acid Glutamine Glycine Histidine Isoleucine Leucine Lysine … Methionine Phenylalanine...
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A8 Two acid dissociation constants (pka) of the amino acid aspartic acid are shown below. The measured isoelectric point (pl) is 3.0. What is the pka of the carboxylic acid side chain? PK, 9.8 pk, 2.1 *H3N он Questions continue over page