A man jumps horizontally from the third floor of a burning building to a rescue trampoline...

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Question

A man jumps horizontally from the third floor of a burning building to a rescue trampoline...

A man jumps horizontally from the third floor of a burning building to a rescue trampoline below. His initial speed is 3.00 m/s. If the third floor window is 11.9 m above the trampoline, how much time (in seconds) will elapse between when he jumps and when he lands on the trampoline?

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Answer 1

Answer #1

Given,

The initial speed, u = 3 m/s

The height of window, h = 11.9m

By using the equation of motion,

v² - u² = 2 g h

v² - (3)² = 2 * 9.8 * 11.9

v² = 242.24

v = 15.56 m/s

We know,

v = u + g t

t = (v - u) / g

t = (15.56 - 3) / 9.8

t = 1.282 sec

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Answer 2

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A man jumps horizontally from the third floor of a burning building to a rescue trampoline...

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