Question

Define a function that creates a list of all the numbers that are factors of the user's number. For example, if the function is called factor, factor(36) should return [1, 2, 3, 4, 6, 9, 12, 18, 36]. The numbers in your list should be sorted from least to greatest, and 1 and the original number should be included.

Remember to consider negative numbers as well as 0.

Bonus: Have the program print the factors of the users number in a comma separated string, without a comma after the last number, and without the brackets of a Python list. If the user's number is prime, note it.

Answer 1

Here is your answer ::

Code ::

def factors(x):

# For Positive Numbers

# return the list of numbers in the range of 1 to x+1

   if x > 0:
       return [i for i in range(1,x+1) if x%i==0]

# For negative Numbers

# return the list of numbers in the range of x to 0

# Here is x is negative iteration starts from -ve to 0 and checks the condition.

# If x = -4 , the loop runs from - 4 to 0

# if x % i == 0 --> return the number

# This loop runs in the range of ( x, 0 ) and finally the values are returned in the form of list.
   elif x < 0 :
       return [i for i in range(x,0) if x%i==0]

x = input ( "Enter :: " )

print('\n')
print(factors(x))
print('\n')

# Note Down if the user input is Prime
x = abs(x) # used abs() function to check prime for negative numbers also
if x == 1 or x == 0:
print ""
else:
tester=2
checker = True
while tester != x:
if x%tester == 0:
print ""
checker = False
break
tester+=1
if checker == True:
print "User input is Prime"

Output for all test cases ::