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H2S (g) ---------> 1/8 S8 (s) + H2 (g) delta H rxn = +20.2 kJ What...

H2S (g) ---------> 1/8 S8 (s) + H2 (g)

delta H rxn = +20.2 kJ

What is delta H when 25.00g of S8 reacts?

Is correct answer +1.97kJ or +15.7kJ?

Could you please explain your answer for me?

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Answer #1

H2S (g) ---------> 1/8 S8 (s) + H2 (g)

delta H rxn = +20.2 kJ

mass of S8 = 25.00 g

moles of S8 = 25.00 /256.5 = 0.0975

1/8 mol S8   --------> 20.2 kJ

0.0975 mol S8   -------->   ??

delta Hrxn = 0.0975 x 20.2 x 8

delta Hrxn    = 15.7 kJ

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