1. [Range of imm/addr] Answer questions for the following instructions:
a) lw $t0, addr($s0) # what is the range of addr in the power of 2? what number of bits?
b) beq $t0, $s0, addr # what is the range of addr in the power of 2? what number of bits?
a) addi $t0, $s0, imm # what is the range of immin the power of 2? what number of bits?
a) j addr # what is the range of addr in the power of 2? what number of bits?
2's signed magnitude are the way addr, imm
a) (-32,768,32,767) 16 bits
b) (-32,768,32,767) 16 bits
c) (-32,768,32,767) 16 bits
d)(-33,554,432,33,554,431) 26 bits
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1. [Range of imm/addr] Answer questions for the following instructions: a) lw $t0, addr($s0) # what...
1. For the MIPS assembly instructions below, what is the corresponding C statement? max: lw $t0, 0($a0) #load the first array value into $t0 addi $t1, $0, 1 #intialize the counter to one loop: beq $t1, $a1, exit #exit if we reach the end of the array addi $a0, $a0, 4 #increment the pointer by one word addi $t1, $t1, 1 #increment the loop counter lw $t2, 0($a0) #store the next array value into $t2 slt $t3, $t0, $t2 beq ...
Implement the following pseudo instructions using the appropriate MIPS instructions: Divi $s0, $s1, imm (imm is a 16-bit value) Mul $s1, $s2, imm (imm is a 16-bit value) Li $t0, imme (load the 32-bit value into register $t0) Blt $to, imme, L (imm is a 16-bit value) Divu $s0, $s1, $s2
Consider the following MIPS code (don't worry about what it does): loop: beq $s0, $s1, done addi $t0, $t0, 7 addi St1, St2, 4 addi $s0, $s0, 1 j loop done: beq St1, $15, skip addi St0, Sto, 1 addi St1, St2, St0 skip addi $t5, $0, 10 beq St1, St5, done j end Compute the branch offset for each beq in number of words away from the branch (e.g., "branch offset is 2") Assume label loop is at location...
1.Please use 5-stage pipeline to describe following MIPS assembly code in non-forwarding pipeline. lw $s0, 0($t0) add $s1, $s0, $s0 mul $s2, $s1, $s0 . 2.Please use 5-stage pipeline to describe following MIPS assembly code in forwarding pipeline. lw $s0, 0($t0) add $s1, $s0, $s0 mul $s2, $s1, $s0 sw $s2, 4($t0)
2.4 For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively. sll $t0, $s0, 2 # $t0 = f * 4 add $t0, $s6, $t0 # $t0 = &A[f] sll $t1, $s1, 2 # $t1 =...
What are the machine codes for the following MIPS assembly codes? a. sub $t0, $s0, $s1 b. lw $t0, 20($s0)
what is the output of the following assembly code ? .data A: .word 84 111 116 97 108 32 105 115 32 . text main:li $v0, 1l li $s0,0 la $s1, A li $t3, 0 loop: slti $t0, $s0, 17 beq: $t0, $zero, end sll $t1, $s0 2 add $t2 $s1 $t1 syscall addi $s0, $s0, 1 j loop end: li $v0, 1 add $a0, $zero, $t3 syscall
1. Given the following instruction sequence for the MIPS processor with the standard 5 stage pipeline $10, S0. 4 addi lw S2.0(S10) add sw S2,4(510) $2, $2, $2 Show the data dependences between the instructions above by drawing arrows between dependent instructions (only show true/data dependencies). a. Assuming forwarding support, in what cycle would the store instruction write back to memory? Show the cycle by cycle execution of the instructions as they execute in the pipeline. Also, show any stalls...
MIPS assembly language question
If $s0 has the base address of array A, and A has the following elements: 9, 6, 4, 24, 33, 0, 1; What is the value of $t1 after the instructions are executed? addi $t1, $zero, 20 add $t0, $t1, $S0 lw $t1, (Sto)
Given the big-endian instruction memory map shown below in (b), and the initial values $t1 0XE7eeeADD, $s5 = 0x80000010 . We execute the following instructions: lw $t1, 12($s5) andi $t1, $t1, 0x3E0000A9 sra $s5, $s5, 3 addi $se, $s5, 2 sw $t1, -4($s0) Answer the following questions: (a) What values are contained in $se and sti after executing the above instructions? Write your answers in Hex format.
Given the big-endian instruction memory map shown below in (b), and the initial...