Question

#include <iostream>

#include <vector>

#include <iomanip>

using namespace std;

int main() {

const int NUM_ITEMS = 8;

vector <double> inverse(NUM_ITEMS);

int j;

double temp;

for (int i = 0; i < NUM_ITEMS; i++) {

inverse.at(i) = 1 / (i + 1.0);

}

cout << fixed << setprecision(2);

cout << "Original vector..." << endl;

for (int i = 0; i < NUM_ITEMS; i++) {

cout << inverse.at(i) << " ";

}

cout << endl;

cout << "Reversed vector..." << endl;

for (int i = 0; i < NUM_ITEMS; i++) {

cout << inverse.at(i) << " ";

}

return 0;

}

Original vector...

1.00 0.50 0.33 0.25 0.20 0.17 0.14 0.13

Reversed vector...

0.13 0.14 0.17 0.20 0.25 0.33 0.50 1.00

Using the code below write code to reverse the order of the vector. In other words, the value stored at index 0 will be swapped with the last item in the vector, the value stored at index 1 will be swapped with the next to last item in the vector, etc.  

Answer 1

#include <iostream>
#include <vector>
#include <iomanip>

using namespace std;

int main() {
    const int NUM_ITEMS = 8;
    vector<double> inverse(NUM_ITEMS);
    int j;
    double temp;
    for (int i = 0; i < NUM_ITEMS; i++) {
        inverse.at(i) = 1 / (i + 1.0);
    }
    cout << fixed << setprecision(2);
    cout << "Original vector..." << endl;
    for (int i = 0; i < NUM_ITEMS; i++) {
        cout << inverse.at(i) << " ";
    }
    cout << endl;

    for (int i = 0; i < NUM_ITEMS / 2; ++i) {
        temp = inverse.at(i);
        inverse.at(i) = inverse.at(NUM_ITEMS - i - 1);
        inverse.at(NUM_ITEMS - i - 1) = temp;
    }

    cout << "Reversed vector..." << endl;
    for (int i = 0; i < NUM_ITEMS; i++) {
        cout << inverse.at(i) << " ";
    }
    return 0;
}