Question

Find the regression​ equation, letting the diameter be the predictor​ (x) variable. Find the best predicted circumference of a beachball with a diameter of 44.6 cm. How does the result compare to the actual circumference of 140.1 ​cm? Use a significance level of 0.05. Find the regression​ equation, letting the diameter be the predictor​ (x) variable. Find the best predicted circumference of a beachball with a diameter of 44.6 cm. How does the result compare to the actual circumference of 140.1 ​cm? Use a significance level of 0.05.
Baseball Basketball Golf Soccer Tennis ​Ping-Pong Volleyball
Diameter 7.3 24.3 4.3 22.2 7.0 4.1 21.1
Circumference 22.9 76.3 13.5 69.7 22.0 12.9 66.3\

The regression equation is y bar equals=_____ + ______x.
​(Round to five decimal places as​ needed.)

The best-predicted circumference for a diameter of 44.6cm is _________cm. ​(Round to one decimal place as​ needed.)

How does the result compare to the actual circumference of 140.1​cm?
A.Since 44.6cm is within the scope of the sample​ diameters, the predicted value yields the actual circumference.

B.Even though 44.6cm is beyond the scope of the sample​ diameters, the predicted value yields the actual circumference.This is the correct answer.

C.Since 44.6cm is beyond the scope of the sample​ diameters, the predicted value yields a very different circumference.Your answer is not correct.

D.Even though44.6 cm is within the scope of the sample​ diameters, the predicted value yields a very different circumference.

Answer 1

1)

The regression equation is y^ =0.00639+3.14015x

2)

The best-predicted circumference for a diameter of 44.6cm =140.1

3)

B.Even though 44.6cm is beyond the scope of the sample​ diameters, the predicted value yields the actual circumference.