In C programming language for Tiva Launchpad, what are the differences between following instructions?
LDR R0, [R1]
LDRH R0, [R1]
LDRB R0, [R1]
Load instructions (in general) come in the follow form:
LDR {type}{cond} Rt, [Rn {, #offset}]
The 'type' is optional and is described in the table above, where you can choose to work with halfwords, bytes as well as signed or unsigned bytes or halfwords. You also have the option to load or store multiple registers.
You also have the option of adding a condition code to the instruction (cond), which is used to set the condition flags held in the Current Program Status Register (CPSR).
1. The LDR pseudo-instruction loads a register with either:
a 32-bit constant value
an address.
Syntax
The syntax of LDR is:
LDR{condition} register,=[expression | label-expression]
where:
condition:
is an optional condition code.
register:
is the register to be loaded.
expression
evaluates to a numeric constant:
If the value of expression iswithin range of a MOV or MVN instruction, the assembler generates the appropriate instruction.
If the value of expression is not within range of a MOV or MVN instruction, the assembler places the constant in a literal pool and generates a program-relative LDR instruction that reads the constant from the literal pool.
The offset from the pc to the constant must be less than 4KB. You are responsible for ensuring that there is a literal pool within range. See LTORG directive for more information.
label-expression
is a program-relative or external expression. The assembler places the value of label-expression in a literal pool and generates a program-relative LDR instruction that loads the value from the literal pool.
The offset from the pc to the value in the literal pool must be less than 4KB. You are responsible for ensuring that there is a literal pool within range. See LTORG directive for more information.
If label-expression is an external expression, or is not contained in the current area, the assembler places a linker relocation directive in the object file. The linker ensures that the correct address is generated at link time.
2.
Syntax
LDR[condition]B dest, addr_mode
where:
|
condition |
One of 16 conditions. Refer to Condition Code Status. |
|
dest |
destination register |
Description:
The LDRB instruction loads a byte from addr_mode into dest . This byte is zero-extended into a 32-bit word enabling 8-bit memory data to be manipulated. It also enables PC-relative addressing if used as a base register. The condition needs to be a valid value; else the instruction is rendered an NOP.
3. LDRB (Load Register Byte) loads a byte from memory, zero-extends it to form a 32-bit word, and writes the result to a general-purpose register.
LDR[condition]H dest, addr_mode
where:
|
condition |
One of 16 conditions. Refer to Condition Code Status. |
|
dest |
destination register |
Description
The LDRH instruction loads a halfword from addr_mode into dest . The halfword is zero-extended into a 32-bit word enabling 16-bit memory data to be manipulated. It also enables PC-relative addressing if used as a base register. The condition needs to be a valid value; else the instruction is rendered an NOP.
In C programming language for Tiva Launchpad, what are the differences between following instructions? LDR ...
indicate what each line of code means
2. Explain how the following ARM program can be used to determine whether a computer is big- endian or little-endian: MOV R0, #100 LDR R1, -0xABCD876 STR R1, [RO] LDRB R2, [R0, #1] R1-0xABCD876
Suppose r0 = 0 times 20008000, and the memory layout is as follows: (a) What is the value of r1 after running LDR r1, [r0] if the system is little endian? What is the value if the system uses the big-endian? b) Suppose the system is set as little endian. What are the values of r1 and r0 if the following instructions are executed separately? LDR r1, [r0, #4] LDR r1, [r0], #4 LDR r1, [r0, #4]!
Write C code that perform the same as the assembly code. Hint:data is an integer avariable in C. OUT is a name of a function:- //code part is the following.. L1 LDR R0, =0X006 ;The hexadecimal of 0110 is 0x006 L2 LDR R1, =data L3 LDR R2, [data] L4 AND R2, #0X006 L5 CMP R2, #0X006 L6 BLEQ OUT L7 ..................
4. What will r0 and r1 contain after each of the following instructions? Consider the instructions in sequence. Give your answers in decimal format. mov r0,#1 @ r0 =_____________ mov r1,#0x30 @ r0= _____________ r1= _____________ orr r1,r1,r0 @ r0= _____________ r1= _____________ lsl r1,#0x2 @ r0= _____________ r1= _____________ orr r1,r1,r0 @ r0= _____________ r1= _____________ eor r0,r0,r1 @ r0= _____________ r1= _____________ lsr r1,r0,#3 @ r0= _____________ r1= ______________
Consider the initial content of the memory as shown in the figure below, what will be the content of R1 after executing the following instructions?? Assume the content of R2 is 0 times 0000.1008 and little-endian addressing is used. LDR R1, [R2] LDRB R1, [R2] LDRH R1, [R2] LDRSB R1, [R2] LDRSH R1, [R2]
2. Encode the following four TM4C Thumb-2 instructions using 16-bit instructions if possible: LDR R3,[R0] MOV R2,R3 STR R6, [SP, #0x08] RSB R11,R7,R7, LSL #2 Note: uVision may NOT give the 16-bit answer for encoding when you check.
Ox00000000. Initially N-Z=C=V=0. Find the new values ofr3, N, Z, C, and V running each following instructions 5. Suppose r0 0XFFFFFFFF, rl = 0x00000001 and r2 independently (i.e. same starting values for each case). Not graded: check results with TIVA. ADDS r3, r0, r2 а. b. SUBS r3, r1, r0 ; note: not the LSLS instruction r3, r0, #1 LSL с.
Write an equivalent C function and explain what it computes.
3. (10 marks) The following is the assembly language translation of a C function mystery: r3, [r0, #0] r3, #0 L3 ldrb cmp beq r3, #0 mov L4: r3, r3, #1 r2, [ro, r3] r2, #0 L4 add ldrb cmp bne .L3: ro, r3 lr mov bx Annotate each line of the function with commentss to explain what each line does. Write an equivalent C function and explain what it...
Question 5 What are the addressing modes of the following assembly instructions? 1) (1 point) LDR R1, R2] A. Immediate mode B. Register mode C. Relative mode D. Indirect mode 2) (1 point) SUB RO, R1, R4 A. Immediate mode B. Index mode C. Register mode D. Indirect mode 3) (1 point) BMI target A. Immediate mode B. Register mode C. Relative mode D. Indirect mode Question 6 Which of the following utility software tools can translate high level language...
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