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A projectile is launched at 59.5 m/s from a height of 83.5m, at the edge of...

A projectile is launched at 59.5 m/s from a height of 83.5m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting he ground below. Find the time it takes to hit the ground at the base of the cliff.

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Answer #1

Considering motion along vertical

h = ho + ut - 0.5 gt^2

0 = 83.5 + 59.5* t - 4.9 t^2

Time, t = 13.41 sec

Comment in case any doubt please rate my answer.....

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