A jeweler wishes to show off the intrinsic brilliance of their prize diamond by giving it...
A jeweler wishes to show off the intrinsic brilliance of their prize diamond by giving it an antireflective coating for light of wavelength 565 nm in air. What is the minimum thickness the jeweler needs for a coating material with an index of refraction of 1.45? The index of refraction of diamond is 2.41.
Homework Answers
nc = index of refraction of the coating material = 1.45
= wavelength in
air = 565 nm
t = thickness of the coating
for anti reflective coating , we have
t = /(4n)
t = 565/(4 x 1.45)
t = 97.4 nm
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