Question

You can transmit 1.54 Gbps in a channel you use frequently. You want to transmit at 4.32 Gbps. How much wider must your channel be than its current bandwidth? (Please don't copy from a previous answer)

Answer 1

According to shannon capacity formulae for a noisless channel.

C = 2*B*(M). where C is the channel capacity in bits per second,B is the channel bandwith and M is the number of symbols used.

In our case:

C1 = 1.54 Gbps and C2 = 4.32 Gbps

considering number of symbols used is same for both cases taking ratio we will get

equating the values we will get : B2 = * B1

that is B2 = 2.8052 * B1;

Therefore in short the current bandwith should be atleast 3 times the original bandwith.