Ligand A and protein B bind to each other with a Kd of 15 μM. If...
Ligand A and protein B bind to each other with a Kd of 15 μM. If the total concentrations of A and B are 456 μM and 1,060 μM, respectively, then what fraction of A is bound?
Homework Answers
In a bimolecular equilibrium reaction
[A] + [B] ==> [AB], Ka = [AB] / [A][B]
[AB] ==> [A] +[B]
Kd = [A][B]/[AB]
From this the fraction of A Bound = [AB] / [A] + [AB] = 1/ ([A]/[AB] + 1) = 1/(Kd/[B] +1) = [B] / Kd + [B]
[A] (ligand) = 456 uM
[B] (protein) = 1060 uM
Kd = 15 uM
Fraction of A Bound = 1060 uM /(15 + 1060) uM = 0.9860
Fraction of Ligand A bound to protein = 0.9860.
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