What is the spin multiplicity of these molecules?
N2
O2
F2
HCl
HBr
HI
What is the spin multiplicity of these molecules? N2 O2 F2 HCl HBr HI
What is the spin multiplicity of these molecules? HCl, HBr, and HI
Classify these diatomic molecules as diamagnetic or paramagnetic: O2, F2, B2, C2, N2
Consider the following list of molecules: O2, H2O2, HF, N2, CO, NO, F2 Out of the list above, how many of the molecules could be classified as a “homonuclear diatomic”? A. 1 B. 2 C. 3 D. 4 3
Which of the following molecules would be expected to be attracted to a magnetic field? F2 N2 O2 N2 and O2 N2 only F2 and O2 F2 and N2 O2 only
Bond strength decreases dramatically in the diatomic molecules from N2 (942 kJ mol-1) to O2 (495 kJ mol-1) to F2 (155 kJ mol-1). What accounts for this behavior?
Which of the following molecules is nonpolar? a. H2 b. HF c. HCl d. HI e. HBr Which of the following molecules can participate in Hydrogen bonding? a. HF b. CO2 c. CH4 d. H2S Which of the following molecules is polar? a. H2O b. CO2 c. CH4 d. N2 e. None of the above In lab, temperature changes caused by ________________ of liquids will be related to the strength of intermolecular forces. a. Evaporation b. Mass c. Density d....
Question 1) By drawing molecular orbital diagrams for B2, C2,
N2, O2, and F2, predict which of these homonuclear diatomic
molecules are magnetic.
Question 2) Based on the molecular orbital diagram for NO, which
of the following electronic configurations and statements are most
correct?
Arrange the following gases in order of decreasing density at STP: HCl, HBr, Ne, O2
Question 3 1 pts Given the bond dissociation energies (in kJ/mol) for the following diatomic molecules Cl2 (243), F2 (158), H2 (436), O2 (498), N2 (945) choose the one(s) that could be broken by using blue light (=465 nm). F2 and Cl2 o F2 F2, C12, H2, O2 and N2 F2, Cl2 and H2 F2, Cl2, H2 and 02
5. Predict the major product for each of the following reactions HCl а. b. HI HBr с. 5. Predict the major product for each of the following reactions HCl а. b. HI HBr с.