Question

Given the following program segment: int limit = 4; int first = 5 int j; for...

Given the following program segment:

int limit = 4;

int first = 5

int j;

for (j=1; j <= limit; j++)

{

cout << first * j << endl;

first = first + (j -1);

}

cout << endl;

write a while loop and a do...while loop that both have the same output.

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Answer #1

int limit = 4;
int first = 5
int j = 1;
while(j <= limit)
{
    cout << first * j << endl;
    first = first + (j -1);
    j++;
}

int limit = 4;
int first = 5
int j = 1;
do
{
    cout << first * j << endl;
    first = first + (j -1);
    j++;
}while(j <= limit);
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