Question

Create the second part of a Rock, Paper, Scissors game. The game keeps playing as long as the user enters 'Y'. Make this case sensitive; if they enter a lower case y the game will not continue. If the user enters in anything besides upper case Y the game will end.

Your text must exactly match the examples below:

Example 1 with correct input

Let's play Rock, Paper, Scissors

Enter 1 for rock, 2 for paper, 3 for scissors

2

You chose paper

Would you like to play again (Y for yes, N for no)?

Y

Enter 1 for rock, 2 for paper, 3 for scissors

1

You chose rock

Would you like to play again (Y for yes, N for no)?

N

This what I have so far

#include <iostream>
using namespace std;

int main ()
{
int x;

cout <<"Let's play Rock, Paper, Scissors" << endl;
cout <<"Enter 1 for rock, 2 for paper, 3 for scissors" << endl;
cin >> x;
switch (x)
{
case 1:
cout << "You chose rock" << endl;
break;
case 2:
cout << "You chose paper" << endl;
break;
case 3:
cout << "You chose scissors" << endl;
break;
default:
cout << x << " is not a valid choice" << endl;
break;
}
return 0;
}

I want to know how to loop this so I could complete this assignment. I tried different things but they won't compile.

Answer 1

#include <iostream>
using namespace std;

int main ()
{
int x;
char ch = 'y';
cout <<"Let's play Rock, Paper, Scissors" << endl;
while(ch=='y' || ch=='Y'){
    cout <<"Enter 1 for rock, 2 for paper, 3 for scissors" << endl;
    cin >> x;
    switch (x)
    {
    case 1:
        cout << "You chose rock" << endl;
        break;
    case 2:
        cout << "You chose paper" << endl;
        break;
    case 3:
        cout << "You chose scissors" << endl;
        break;
    default:
        cout << x << " is not a valid choice" << endl;
        break;
    }
    cout<<"Would you like to play again (Y for yes, N for no)?"<<endl;
    cin>>ch;
}
return 0;
}