Question

Re-write the following if statement structure as a SWITCH/CASE statement in C++ and Pseudocode:

      X ← 1

      A ← 3
      IF (a is equal to 1) THEN
         x ← x + 5
      ELSE IF (a is equal to 2) THEN
         x ← x + 10
      ELSE IF (a is equal to 3) THEN
         x ← x + 15
      ELSE IF (a is equal to 4) THEN
         x ← x + 20
      ELSE x ← x + 100

      ENDIF

PRINT("x = " + x);

Answer 1

Pseudocode:
--------------
X ← 1
A ← 3
SWITCH(A)
    CASE 1:
        x ← x + 5
        BREAK
    CASE 2:
        x ← x + 10
        BREAK
    CASE 3:
        x ← x + 15
        BREAK
    CASE 4:
         x ← x + 20
         BREAK
    DEFAULT:
        x ← x + 100
ENDSWITCH
PRINT("x = " + x);

================================================

C++ code:
-----------
X = 1
A = 3
switch(A){
    case 1:
        x = x + 5;
        break;
    case 2:
        x = x + 10;
        break;
    case 3:
        x = x + 15;
        break;
    case 4:
         x = x + 20;
         break;
    default:
        x = x + 100;
}
cout<<"x = "<<x<<endl;