Question

Question 5: Consider the following C++ program. switch(x) case 1: if (x > 1) case 2: if (x > 3) case 3: cout<<"Epic Beats!" << endl; case 4: cout << "Chill Vibes" << endl; break; case 5: cout << "Sweet Jazz" << endl; break; default: cout << "Invalid input. Try again."; A. What is the output if x = 1? B. What is the output if x = 3? C. What is the output if x = 2? D. What is the output if x = 9?

Answer 1

In switch case,if we didn't write the break for each case.Then the program continues to next case ,executing the statements untill a break.

A). For x =1: Output = Chill Vibes

If x =1 :it will go to case 1: Without break switch will be look like below.

case 1:

if(x>1)

{

if(x>2)

{   

cout<< "Epic Beats!"<<endl;

}

}

cout << "Chill Vibes"<<endl;

break;

So it check the condition x>1 (1>1).It is false.So it doesn't goes to next statement if(x>2).So it doesn't execute the cout<< "Epic Beats!". Next statement is cout << "Chill Vibes";

So for x = 1.It prints Chill Vibes.

B). For x =3: Output :

Epic Beats!

Chill Vibes

If x =3:it will go to case 3: Without break switch will be look like below.

case 3:

cout<< "Epic Beats!"<<endl;

cout << "Chill Vibes"<<endl;

break;

Tt executes the statement cout<< "Epic Beats!";.It prints Epic Beats! and next statement is  cout << "Chill Vibes";.It prints Chill Vibes.

So for x = 3.It prints

Epic Beats!

Chill Vibes

C). For x =2: Output = Chill Vibes

If x =2 :it will go to case 2: Without break switch will be look like below.

case 2:

if(x>2)

{   

cout<< "Epic Beats!"<<endl;

}

cout << "Chill Vibes"<<endl;

break;

In this code checks the x>2(2>2).This condition is false.So it doesn't print Epic Beats!.Next it executes the statemen cout << "Chill Vibes";.It prints Chill Vibes

D). For x =9: Output = Invalid input.Try again.

In switch case , If x value is not equal to any case.Then switch case execute the default case.

For x =9,default will execute.So it executes cout<<"Invalid input.Try again."<<endl;

It prints the Invalid input.Try again.