Convert the below code into if else selection: #include <iostream> using namespace std; int main() { int num; sin. >> num; switch (num) { case 1: cout << "Casel: Value is: << num << endl; break; case 2: break; case 3: cout << "Case3: Value is: " << num << endl; break; default: cout << "Default: Value is: << num << endl; break; } return; }
41. Executing the "continue" statement from within a loop causes control to go A. to the next line of code B. out of the loop C. to the beginning of the loop D. to check the loop condition for repeating the loop E. none of the above 42. The 'default' statement inside a 'switch()' is optional. T__ F__ 43. The following 'switch' implementation is legal: int i = 2; ...
can you show me the details please.
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13. What is the output of the following program? #include <iostream.h> void main() { int x; 1/ declare variable for (x = 1; x <= 5; x++) { // loop 5 times switch (x) { case 1: cout << x < // switch value of // if "x" is equal // display "X", but endl; case 2: cout << x << endl; // if "x" is equal // display "x", but...
#include <iostream> #include <conio.h> #include<limits> using namespace std; int main(){ char oparand, ch = 'Y'; int num1, num2, result; while(ch == 'Y'){ cout << "Enter first number: "; cin >> num1; while(1){//for handling invalid inputs if(cin.fail()){ cin.clear();//reseting the buffer cin.ignore(numeric_limits<streamsize>::max(),'\n');//empty the buffer cout<<"You have entered wrong input"<<endl; cout << "Enter first number: "; cin >> num1; } if(!cin.fail()) break; } cout << "Enter second number: "; cin >> num2; while(1){ if(cin.fail()){ cin.clear(); cin.ignore(numeric_limits<streamsize>::max(),'\n'); cout<<"You have entered wrong input"<<endl; cout <<...
C++
What output does the following program produce?
int getValue(int a, int b, int n); int main() cout << getValue(1, 7, 7) << endl; return 0; } // end main int getValue(int a, int b, int n) int returnValue = 0; cout << "Enter: a = " < a << " b = " << b << endl; int c = (a + b)/2; if (C* C <= n) return value = c; else returnValue = getValue(a, C-1, n); cout...
what is the output of the following code segment?
C++
g. int arr[3][4]; for (int i = 0; i < 3; i++) for (int j = 0; j < 4; j++) arr[i][j] =i*4 + j; for (int i = 0; i < 3; i++) for (int j = 0; j < 4; j++) cout << arr[i][j] << " "; h. int next(int & x) { x= x + 1; return (x + 1); int main() { int y = 10;...
Could use some help with this, Instructions: You will need to add an input statement for the grade variable to this code. Also add a for loop so that you can enter more than one grade. Code the for loop so that at least 7 grades can be entered. #include <iostream> #include <string> using namespace std; void main() { char grade; for (int x = 0; x < 7; x++) { cout << "Enter a...
The switch Statement C++program This lab work with the switch statement. • Remove the break statements from each of the cases. What is the effect on the execution of the program? • Add an additional switch statement that allows for a Passing option for a grade of D or better. Use the sample run given below to model your output. Sample Run: What grade did you earn in Programming I? YOU PASSED! An A - excellent work! The following is...
What is the output of the program? int function1( int x, int& y) { if( x % 2 == 0) { x = x + y; } y = y - x; return x; } int main() { int a, b, result; cin >> a >> b; result = function1(a, b); cout << "a = "<< a << ", b = " << b << endl; cout << "result = " << result << endl; } Please make comments...
Write a program that will accept an integer as input from the user and test if that input is an even number. It should also test if the input is evenly divisible by 6. The program should display “Even” if the user’s input is even. It should additionally display “divisible by 6” if the user’s input is evenly divisible by six. #include <iostream> using namespace std; int main(){ return 0; } Convert the following switch statement to an if-...