Question

13. What is the output of the following program? #include <iostream.h> void main() { int x; 1/ declare variable for (x = 1; x <= 5; x++) { // loop 5 times switch (x) { case 1: cout << x < // switch value of // if "x" is equal // display "X", but endl; case 2: cout << x << endl; // if "x" is equal // display "x", but case 3: cout << x < break; endl; // if "x" is equal // display "X" // break from switc default: cout < x + 1 < // if "x" is # from endl; // display "X +1" cout << endl;

can you show me the details please.
thank you

Answer 1

As no break statement in case 1 and case 2
When x is 1, It prints value of x three times

As no break statement in case 2
When x is 2, It prints value of x two times

As there is a break statement in case 3
When x is 3, It prints value of x one times

Any value of x other than 1,2,3 prints the value of x+1 to console.

Loop runs for values of x from 1 to 5
When x is 1, It prints
1
1
1

When x is 2, It prints
2
2

When x is 3, It prints
3

When x is 4, It prints
5

When x is 5, It prints
6

So, output is
1
1
1
2
2
3
5
6