Suppose that 28% of the people that come into Pierre’s order a double chocolate mochaccino, while...
Suppose that 28% of the people that come into Pierre’s order a double chocolate mochaccino, while 72% do not. Assume that each person is independent of the any other.
Suppose twelve people show up at the coffee shop at the same time. What is the probability that exactly six of them will order the mochaccino?
Provide the following:
Number of combinations:
Final answer:
Homework Answers
X ~ Bin ( n , p)
Where n = 12 , p = 0.28
Number of combinations 12C6 = 12! / [ ( 12 - 6)! * 6! ] = 924
Binomial probability distribution
P(X) = nCx * px * ( 1 - p)n-x
P(X = 6) = 12C6 * 0.286 * ( 1 - 0.28)6
= 0.0620
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