If the mean of a normally distributed population is 580 with st.dev of 62. What percent of the data would we find below 535?
a) 72.6%
b) 27.4%
c) 23.4%
d) none of these
e) 76.6%
Solution :
Given that ,
mean =
= 580
standard deviation =
= 62
P(X<535 ) = P[(X-
) /
< (535 -580) /62 ]
= P(z <-0.73 )
Using z table
= 0.2327
answer=23.4%
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