Suppose that we want to estimate the population average price μ for the grapes per pound. Assume that the price per pound follows the normal distribution. (a). If for a random sample of grape prices obtained from 20 different stores, the sample average price X-bar = $ 1.33 with a sample standard deviation (price) s = $ 0.30 then construct a 95 % confidence interval for μ . (5 points) (b). If the average price obtained from 50 different stores is X-bar = $ 1.48 with the standard deviation σ = $ 0.25 then construct a 99 % confidence interval for μ. (5 points) (c ). State the assumptions that you are making in order to construct the confidence intervals in parts (a) and (b). (6 points)
a) At 95% confidence interval the critical value is t* = 2.093
The 95% confidence interval for
is
+/-
t* * s/
= 1.33 +/- 2.093 * 0.3/
= 1.33 +/- 0.14
= 1.19, 1.47
b) At 99% confidence interval the critical is z* = 2.58
The 99% confidence interval for
is
+/-
z* *
= 1.48 +/- 2.58 * 0.25/
= 1.48 +/- 0.09
= 1.39, 1.57
c) The data is a simple random sample.
The sample values are independent of each other.
The sample size is less than or equal to 10% of the population.
Suppose that we want to estimate the population average price μ for the grapes per pound....
A study was carried out to estimate the average GPA (μ) of undergraduates at a universtiy. Assume that the standard deviation sigma (σ) of their GPA is 0.30. From a random sample of students, researcher finds (3.30, 3.60) to be a 87% confidence interval for the average GPA. What was the researcher's sample size? Round up answer to an integer.
Answers only is fine! Find the critical value zc necessary to form a confidence interval at the level of confidence shown below. c=0.92 Find the margin of error for the given values of c, σ, and n. c = 0.95, σ =2.4, n = 8.1 Level of Confidence. zc 90% 1.645 95% 1.96 99% 2.575 Construct the confidence interval for the population mean μ. c=0.98, x=9.5, σ=0.3, and n= 52 Construct the confidence interval for the population mean μ. c=0.95, x=16.7, σ=6.0, and n=...
1. A random sample of 25 observations was selected from a normally distributed population. The average in the sample was 84.6 with a variance of 400.a. Construct a 90% confidence interval for μ.b. Construct a 99% confidence interval for μ.c. Discuss why the 90% and 99% confidence intervals are different.d. What would you expect to happen to the confidence interval in part (a) if the sample size was increased? Be sure to explain your answer.
A random sample of 175 items is drawn from a population whose standard deviation is known to be σ = 50. The sample mean is x¯x¯ = 920. (a) Construct an interval estimate for μ with 95 percent confidence. (Round your answers to 1 decimal place.) The 95% confidence interval is from to (b) Construct an interval estimate for μ with 95 percent confidence, assuming that σ = 100. (Round your answers to 1 decimal place.) The 95% confidence interval is...
Suppose that prices of Fuji apples are normally distributed. Ryan selected a simple random sample of 12 grocery stores and found that the mean price of Fuji apples at these stores was $1.84 per pound and that the standard deviation was $0.14 per pound. Ryan plans to use this information to construct a confidence interval for u, the mean price of a pound of Fuji apples. Have the requirements for a one-sample t-confidence interval been met? The requirements the population...
Each of the following is a confidence interval for μ = true
average (i.e., population mean) resonance frequency (Hz) for all
tennis rackets of a certain type:
I will rate the answer, thank
you!
6. -110 points DevoreStat9 7.E.002. My Notes Ask Your Teacher Each of the following is a confidence interval for μ = true average (ie, population mean) resonance frequency (Hz) for all tennis rackets of a certain type: (113.6, 114.4) (113.4, 114.6) (a) What is the value...
10. Fill in the blank. In developing a 96% confidence interval estimate for some normal population mean μ, the population standard deviation σ was 10, The interval estimate was found to be 12.6 ±3.64. Had σ equaled 5, the interval estimate would be 12. Based on a sample of size n 21 drawn from a normal population, the sample mean and sample standard deviation are, respectively, 15.68 and 1.36. We use T-test to test Ho : μ 15 vs H1...
Suppose a random sample of n= 16 measurements is selected from a population with mean μ and standard deviation σ. For each of the following values of μ and σ, give the values of mu Subscript x over bar μ x and sigma Subscript x overbar Baseline .and σx. a. μ=5, σ=3 b. μ=25 σ=16 c. μ =10, σ=32 d. μ=55, σ=84 a. mu Subscript x over bar μ x= sigma Subscript x over bar σ x=_______(Type an integer or...
Suppose a random sample of n=64 measurements is selected from a population with mean μ and standard deviation σ. For each of the following values of μ and σ, give the values of mu Subscript x overbarμx and sigma Subscript x overbar Baseline .and σx. a. μ =11, σ=22 b. μ=121 σ=64 c. μ=22 σ=32 d. μ=11 σ=160 a. mu Subscript x over bar μ=_________ sigma Subscript x over bar σx=n_______(Type an integer or a decimal.) b. mu Subscript x...
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x overbarx, is found to be 107,and the sample standard deviation, s, is found to be 10. (a) Construct a 95% confidence interval about μ if the sample size, n, is 25. (b) Construct a 95% confidence interval about μ if the sample size, n, is 13. (c) Construct an 80% confidence interval about μ if the sample size, n, is...