Question

Write robust python code that take from the user the name of file to open.

Then, take name from the user to search inside the file then display its phone number if found

Answer 1

Code:

def fetch_phone_number():
    # Enter the file name which you wish to open
    filename = input("Enter the filename  to be opened")
    dict = {}
    try:
        # Open the file in read mode
        with open(filename, 'r') as fp:
            # read the file line by line
            line = fp.readline()
            while line:
                line = line.split()

                # storeall the usernames with phone numbers in a dictionary
                dict.update({line[0]: line[1]})
                line = fp.readline()

            # If user exist print the phone number
            # otherwise handle the exception
            user_name = input("Enter the user_name to  be searched")
            if dict.get(user_name) is not None:
                print(dict.get(user_name))
            else:
                print("User does not exist")

    except FileNotFoundError:
        print("File does not exist")


fetch_phone_number()