Question

1.3 Write a function to output an arbitrary double number (which might be negative using only printDigit for VO
Write a recursive function that returns the number of 1 in the binary representation 1 in the representation of N/2 plus 1, if N is odd

Answer 1

Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries

Brother since printDigit is not given so I am returning output of function to main. In case any change please comment.

#include <iostream>
#include<cstdlib>
#include<ctime>
using namespace std;
double func()
{
double num=(double)rand()/(double)RAND_MAX;
return num*10.0-5.0;
}
int main()
{
srand(time(NULL));
cout<<func();
return 0;
}

2)

#include <iostream>
#include<cstdlib>

using namespace std;
int func(int n)
{
if(n==0)
return 0;
else
{
if(n%2==0)
return func(n/2);
else
return func(n/2)+1;
}
}
int main()
{
cout<<func(63);
return 0;
}

Kindly revert for any queries

Thanks.