Question

Considering the following code, what result should be expected?

# include <stdio.h>
int functionX (int number1, int number2);
int main ( )
{
int a = 2;
int b = 4;
int c = 8;
c = functionX(a, b);
printf("%d", c);
return 0;
}
int functionX (int number1, int number2)
{
int result = 0;
for (int number = number1; number < number2; number++)
{result = result + number;}
return result;
}

(a) 5
(b) 7
(c) 9
(d) 11

Answer 1

Answer is (a) 5
Let's see how:

#include <stdio.h>
//This is function prototype
int functionX (int number1, int number2);
//main function
int main ( )
{
//this is an integer variable a initialized as 2
int a = 2;
//this is an integer variable b initialized as 4
int b = 4;
//this is an integer value c with an initial value as 8
int c = 8;
//calling the function functionX and storing its return value in variable c and sending a and b as parameters to the function
c = functionX(a, b);
//printing the value of c
printf("%d", c);
return 0;
}

//function definition
int functionX (int number1, int number2)
{

//for the current call number1 = 2 and number2 = 4
int result = 0; //initializing a variable result
//this for loops runs from 2 to 4 that is it runs twice for values 2,3 of the variable number
for (int number = number1; number < number2; number++)
//in each iteration the number is added so the numbers added were 2 and 3
{result = result + number;}

//which results to be 5 which is the returned value and which will be stored in c and will be displayed

return result;
}

OUTPUT:

Thank You! Feel free to ask any questions in the comment section.