MATLAB %% T = 1; N = 11; np = 2; dt = 0.001; tmax =...
MATLAB
%%
T = 1;
N = 11;
np = 2;
dt = 0.001;
tmax = np*T;
t = -tmax:dt:tmax;
%% Function 1
%the following code was used to create the x(t) function
xrange = floor((T/dt)/15);
x1 = linspace(0,1,xrange);
x2 = x1(end-1:-1:1);
x3 = linspace(0,2,2*xrange);
x4 = x3(end-1:-1:1);
x5 = zeros(1,xrange);
x6 = x1;
x7 = 2*ones(1,xrange);
x8 = 1+x2;
x9 = -0.5*ones(1,xrange);
x10 = x1/2-0.5;
xtemp = [x1 x2 x3 x4 x5 x6 x7 x8 x9 x10];
ztemp = zeros(1,floor(T/dt)-length(xtemp));
xtT = [ztemp xtemp];
tT = dt:dt:T;
xt = 0;
for nn = 1:np
xt = [xtT xt xtT];
end
plot(t,xt)
axis([-tmax tmax -1 3])
grid on
xlabel('Time(s)');
%%
% Determine ak coefficients for x(t)
% Plot the approximation of x(t) using ak coefficients for
|k|<=11
%% function 2
% x2(t) = sin(4*pi*t) 0<t<1/2
% x2(t) = 0 1/2<t<1
% x2(t) = x2(t+1)
% Determine ak coefficients for x2(t)
% Plot the approximation of x2(t) using ak coefficients for
|k|<=11
Homework Answers
ANSWER:
Given that
Executable Code:
T = 1;
N = 11;
np = 2;
dt = 0.001;
tmax = np*T;
t = -tmax:dt:tmax;
%% Function 1
%the following code was used to create the x(t) function
xrange = floor((T/dt)/15);
x1 = linspace(0,1,xrange);
x2 = x1(end-1:-1:1);
x3 = linspace(0,2,2*xrange);
x4 = x3(end-1:-1:1);
x5 = zeros(1,xrange);
x6 = x1;
x7 = 2*ones(1,xrange);
x8 = 1+x2;
x9 = -0.5*ones(1,xrange);
x10 = x1/2-0.5;
xtemp = [x1 x2 x3 x4 x5 x6 x7 x8 x9 x10];
ztemp = zeros(1,floor(T/dt)-length(xtemp));
xtT = [ztemp xtemp];
tT = dt:dt:T;
xt = 0;
for nn = 1:np
xt = [xtT xt xtT];
end
plot(t,xt)
axis([-tmax tmax -1 3])
grid on
xlabel('Time(s)');
%%
% Determine ak coefficients for x(t)
% Plot the approximation of x(t) using ak coefficients for
|k|<=11
%% function 2
% x2(t) = sin(4*pi*t) 0<t<1/2
% x2(t) = 0 1/2<t<1
% x2(t) = x2(t+1)
% Determine ak coefficients for x2(t)
% Plot the approximation of x2(t) using ak coefficients for
|k|<=11
Expected output:
Now, let’s assume that the distribution of codons is not uniformly random. We also assume that...
Now, let’s assume that the distribution of codons is not uniformly random. We also assume that only 5 codons {C1,C2,C3,C4,C5} appear in a dataset with a set of 10 of observations of codon {X1=C2, X2=C1, X3=C1, X4=C4, X5=C1, X6=C3, X7=C5, X8 =C2, X9=C4, X10=C3}. Compute the probability distribution of the five codons. If C2 is a start codon and C3 is a stop codon, with the distribution you just computed, what is the probability that a start codon (C2) is...
Insulated x1 x 2 x 3 x4 x5 x 6 x7 x8 x9 x10 x1 x12 x13 x14 x15 x16 x17 x18 x19 x20 x21 x22 x23 x2...
Could someone help me to solve this problem? Please explain
the steps
Insulated x1 x 2 x 3 x4 x5 x 6 x7 x8 x9 x10 x1 x12 x13 x14 x15 x16 x17 x18 x19 x20 x21 x22 x23 x24 x25 T 30 ← |T-50C h- 500 W/m2 C T-20 C 1. 2. Write the Finite Volume equation for node 23. [3 points] Write the 23"d line of the coefficient matrix and the right hand side [2 points] [ k-200...
Let X denote the proportion of allotted time that a randomly selected student spends working on...
Let X denote the proportion of allotted time that a randomly selected student spends working on a certain aptitude test. Suppose the pdf of X is otherwise where-1くθ. A random sample of ten students yields data X1 = 0.49, x2-0.94, x3-0.92, X1 0.90, x8-0.65, x9 = 0.77, x10 = 0.97. 0.79, x5-0.86, x6-0.73, x7 = (a) Use the method of moments to obtain an estimator of θ 1 + X 1 + X (1-%)2 Compute the estimate for this data....
Let X denote the proportion of allotted time that a randomly selected student spends working on...
Let X denote the proportion of allotted time that a randomly selected student spends working on a certain aptitude test. Suppose the pdf of X is otherwise where-1くθ. A random sample of ten students yields data X1 = 0.49, x2-0.94, x3 = 0.92, xa 0.90, x8-0.65, x9 = 0.77, x10 = 0.97. 0.79, x5-0.86, x6-0.73, x7 = (a) Use the method of moments to obtain an estimator of θ 1 + X 1 + X (1-%)2 Compute the estimate for...
Find the DTFT a. x1[n]=(.3)^nµ[n] b. x2[n]=(.3)µ[n-1] c. x3[n]=(.3)^n(µ[n]-µ[n-10]) d. x4[n]=(.3)^n(µ[n-1]-µ[n-10]) e. x5[n]=δ[n] f. x6[n]=δ[n-1] g....
Find the DTFT a. x1[n]=(.3)^nµ[n] b. x2[n]=(.3)µ[n-1] c. x3[n]=(.3)^n(µ[n]-µ[n-10]) d. x4[n]=(.3)^n(µ[n-1]-µ[n-10]) e. x5[n]=δ[n] f. x6[n]=δ[n-1] g. x7[n]=δ[n]+3δ[n-1]+7δ[n-3]
identify the leading and lagging measures, find the correlation matrix, and purpose a cause and effect...
identify the leading and lagging measures, find the correlation matrix, and purpose a cause and effect model using the strongest correlations Myatt Steak House 2010 2011 2012 2013 2014 Order Accuracy X1 86.0% 86.0% 89.0% 90.0% 95.0% Timeliness of Delivery X2 84.0% 82.0% 86.0% 93.0% 95.0% Table Cleanliness X3 4.8 4.8 5.1 5.6 5.8 Customer Satisfication X4 93.4% 93.2% 94.2% 95.3% 96.7% Total # Complaints X5 492 467 431 326 310 Customer Referrals X6 6 12 24 48 96 Gross...
Consider the high temperature diffusion of Arsenic at 1619°C for 290 hours into a semi-infinite solid...
Consider the high temperature diffusion of Arsenic at 1619°C for 290 hours into a semi-infinite solid cylinder of pure silicon having a radius R=810 E-6 m. Assume values of Do = 0.218 cm2/s, Q = 332.2 kJ/mole, R = 8.314 J/mole-K and a surface concentration 6E18 atoms/cm3. Determine the concentration at the ten (10) equally spaced distances from the surface listed below. a) Cx(@x0=0.0∙R) = Cx0= ___6E+18_________ C@surface b) Cx(@x1=0.1∙R) = Cx1= _________________ c) Cx(@x2=0.2∙R) = Cx2= ...
function x(t) = sin(4*pi*t) 0<t<1/2 x(t) = 0 1/2<t<1 x(t) = x2(t+1) Determine ak coefficients for...
function x(t) = sin(4*pi*t) 0<t<1/2 x(t) = 0 1/2<t<1 x(t) = x2(t+1) Determine ak coefficients for x(t) Plot the approximation using matlab of x(t) using ak coefficients for |k|<=11
MATLAB code starts here --------- clear T0=2; w0=2*pi/T0; f0=1/T0; Tmax=4; Nmax=15; %--- i=1; for t=-Tmax: .01:Tmax...
MATLAB
code starts here ---------
clear
T0=2;
w0=2*pi/T0;
f0=1/T0;
Tmax=4;
Nmax=15;
%---
i=1;
for t=-Tmax: .01:Tmax
T(i)=t;
if t>=(T0/2)
while (t>T0/2)
t=t-T0;
end
elseif t<=-(T0/2)
while (t<=-T0/2)
t=t+T0;
end
end
if abs(t)<=(T0/4)
y(i)=1;
else
y(i)=0;
end
i=i+1;
end
plot(T,y),grid, xlabel('Time (sec)'); title('y(t) square wave');
shg
disp('Hit return..');
pause
%---
a0=1/2;
F(1)=0; %dc freq
C(1)=a0;
for n=1:Nmax
a(n)=(2/(n*pi))*sin((n*pi)/2);
b(n)=0;
C(n+1)=sqrt(a(n)^2+b(n)^2);
F(n+1)=n*f0;
end
stem(F,abs,(C)), grid, title(['Line Spectrum: Harmonics = '
num2str(Nmax)]);
xlabel('Freq(Hz)'), ylabel('Cn'), shg
disp('Hit return...');
pause
%---
yest=a0*ones(1,length(T));
for n=1:Nmax
yest=yest+a(n)*cos(2*n*pi*T/T0)+b(n)*sin(2*n*pi*T/T0);...
Python 1 import matplotlib.pyplot as plt 2 import numpy as np 3 4 abscissa = np.arange(20) 5 plt....
python
1
import matplotlib.pyplot as plt
2
import numpy as np
3
4
abscissa = np.arange(20)
5
plt.gca().set_prop_cycle(
’
color
’
, [
’
red
’
,
’
green
’
,
’
blue
’
,
’
black
’
])
6
7
class MyLine:
8
9
def __init__(self,
*
args,
**
options):
10
#TO DO: IMPLEMENT FUNCTION
11
pass
12
13
def draw(self):
14
plt.plot(abscissa,self.line(abscissa))
15
16
def get_line(self):
17
return "y = {0:.2f}x + {1:.2f}".format(self.slope,
self.intercept)
18
19
def __str__(self):...
Could someone help me to solve this problem? Please explain
the steps
Insulated x1 x 2 x 3 x4 x5 x 6 x7 x8 x9 x10 x1 x12 x13 x14 x15 x16 x17 x18 x19 x20 x21 x22 x23 x24 x25 T 30 ← |T-50C h- 500 W/m2 C T-20 C 1. 2. Write the Finite Volume equation for node 23. [3 points] Write the 23"d line of the coefficient matrix and the right hand side [2 points] [ k-200...
Let X denote the proportion of allotted time that a randomly selected student spends working on a certain aptitude test. Suppose the pdf of X is otherwise where-1くθ. A random sample of ten students yields data X1 = 0.49, x2-0.94, x3-0.92, X1 0.90, x8-0.65, x9 = 0.77, x10 = 0.97. 0.79, x5-0.86, x6-0.73, x7 = (a) Use the method of moments to obtain an estimator of θ 1 + X 1 + X (1-%)2 Compute the estimate for this data....
Let X denote the proportion of allotted time that a randomly selected student spends working on a certain aptitude test. Suppose the pdf of X is otherwise where-1くθ. A random sample of ten students yields data X1 = 0.49, x2-0.94, x3 = 0.92, xa 0.90, x8-0.65, x9 = 0.77, x10 = 0.97. 0.79, x5-0.86, x6-0.73, x7 = (a) Use the method of moments to obtain an estimator of θ 1 + X 1 + X (1-%)2 Compute the estimate for...
MATLAB
code starts here ---------
clear
T0=2;
w0=2*pi/T0;
f0=1/T0;
Tmax=4;
Nmax=15;
%---
i=1;
for t=-Tmax: .01:Tmax
T(i)=t;
if t>=(T0/2)
while (t>T0/2)
t=t-T0;
end
elseif t<=-(T0/2)
while (t<=-T0/2)
t=t+T0;
end
end
if abs(t)<=(T0/4)
y(i)=1;
else
y(i)=0;
end
i=i+1;
end
plot(T,y),grid, xlabel('Time (sec)'); title('y(t) square wave');
shg
disp('Hit return..');
pause
%---
a0=1/2;
F(1)=0; %dc freq
C(1)=a0;
for n=1:Nmax
a(n)=(2/(n*pi))*sin((n*pi)/2);
b(n)=0;
C(n+1)=sqrt(a(n)^2+b(n)^2);
F(n+1)=n*f0;
end
stem(F,abs,(C)), grid, title(['Line Spectrum: Harmonics = '
num2str(Nmax)]);
xlabel('Freq(Hz)'), ylabel('Cn'), shg
disp('Hit return...');
pause
%---
yest=a0*ones(1,length(T));
for n=1:Nmax
yest=yest+a(n)*cos(2*n*pi*T/T0)+b(n)*sin(2*n*pi*T/T0);...
python
1
import matplotlib.pyplot as plt
2
import numpy as np
3
4
abscissa = np.arange(20)
5
plt.gca().set_prop_cycle(
’
color
’
, [
’
red
’
,
’
green
’
,
’
blue
’
,
’
black
’
])
6
7
class MyLine:
8
9
def __init__(self,
*
args,
**
options):
10
#TO DO: IMPLEMENT FUNCTION
11
pass
12
13
def draw(self):
14
plt.plot(abscissa,self.line(abscissa))
15
16
def get_line(self):
17
return "y = {0:.2f}x + {1:.2f}".format(self.slope,
self.intercept)
18
19
def __str__(self):...
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