4. 6 M aqueous ammonia is added to the silver halides to dissolve one of them....
4. 6 M aqueous ammonia is added to the silver halides to dissolve one of them.
a. Write the equation for the reaction of ammonia with this halide to form a soluble complex. ______________________________________________
b. Why is it necessary to add nitric acid to the supernatant liquid after separating it from the remaining solid?
c. Suppose that, after adding 6 M ammonia, no precipitate remained. Which halide anion(s) do you know are present and which are absent from this particular unknown? Present____________________________ Absent__________________________
Homework Answers
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4. 6 M aqueous ammonia is added to the silver halides to
dissolve one of them....
all 5&6 5.) Solid silver bromide , AgBr, can be dissolved by adding concentrated aqueous ammonia to give the water- soluble silver-ammonia complex ion. AgBr(s) + 2NH,(aq) U Ag(NH), (aq) + Br(a...
all 5&6
5.) Solid silver bromide , AgBr, can be dissolved by adding concentrated aqueous ammonia to give the water- soluble silver-ammonia complex ion. AgBr(s) + 2NH,(aq) U Ag(NH), (aq) + Br(aq) (a) Show that this equation is the sum of two other equations, one representing the dissolution of AgBr into its component ions and the other representing the formation of the silver-ammonium complex from silver ion and ammonia (b) Calculate the equilibrium constant for the above reaction K,(AgBr) =...
2. With the precipitate (AgCl) still present in the test tube, add aqueous ammonia. The precipitate...
2. With the precipitate (AgCl) still present in the test tube, add aqueous ammonia. The precipitate should disappear. This means that silver chloride is soluble in ammonia solution. It is soluble because silver ion and ammonia form a complex called diamminesilver (I) chloride, [Ag(NH3)2]Cl which in solution exists as [Ag(NH)2]* and Cl ions. You could have guessed that this would have happened if you looked over the Table A values of Kr at the end of this lab (and you...
[24]Following questions are based on Experiment #17 "General ation unknown analysis The data and results provided...
[24]Following questions are based on Experiment #17 "General ation unknown analysis The data and results provided pertain to a specific unknown analysis. Provide Answers to the following for this analysis 1 (a) To separate Qualitative Analytical (QA) Group I from the other groups tested in the general cation unknown you must add (b) The precipitate obtained in (a) above was centrifuged and the supernatant liquid decanted. The The warm test tube contained no precipitate. Based on this observation, provide the...
Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below,...
Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below, remember phases. Aluminum is more likely to form a hydrated complex than the other four ions remaining in solution, because of its relatively small size and high charge To separate the Group B2 ion, the solution first is made basic by adding ammonia. In the presence of this weak base the pH is adjusted to 9-10 and the group B ions form insoluble hydroxides....
The precipitate did not dissolve because sulfate ion is too weak a base. The amount of...
The precipitate did not dissolve because sulfate ion is too weak a base. The amount of sulfate ion that reacts with the hydronium ion is too small to cause a shift in the equilibrium sufficient to dissolve a signiticant amount of the insoluble sulfate. In general, the anion of a precipitate must be a stronger base than fluoride ion in order for the precipitate to be dissolved by the addition of a strong acid. After the reactions with barium ion,...
Oxalate ion will interfere with the Group D tests after we make the solution acidic. Also,...
Oxalate ion will interfere with the Group D tests after we make the solution acidic. Also, ammonium ion may prevent the precipitation of Group Dcations as hydroxides in sodium hydroxide solution. Thus, must treat the supernatant liquid left after we have precipitated calcium oxalate, in order to destroy any remaining Oxalate or ammonium ions prior to further analysis. To accomplish this, we transfer the solution to a crucible, add concentrated nitric acid and heat the mixture to dryness in a...
2. How are the Group I cations first precipitated from solution? 3. Write the net-ionic equation...
2. How are the Group I cations first precipitated from solution? 3. Write the net-ionic equation for the initial precipitation of any one Group I cation from your unknown solution. 4. Lead(II) chromate is used as a yellow pigment in paints. Write the net-ionic equation for its formation in this Experiment during the confirmatory test for lead(II). 5. When ammonia is added to a white precipitate of mercury(I) chloride, the precipitate turns grayish-black. Write the net-ionic equation for what happens,...
Group 1 Flowchart Use the following chemical facts to construct a flow chart for this lab:...
Group 1 Flowchart Use the following chemical facts to construct a flow chart for this lab: 1 Group 1 cations are Ag, Hg, and Pb 2. AgH a and Pbare given to you in lab as their nitrates which are soluble in water (denoted by as) 3 AgHgand Pb are the only common ions that form a precipitate (denoted by with the Cl ion, presented as Hcl They all form white precipitates. 4. These Group 1 precipitates are separated from...
Group I Cations A INTRODUCTION Most metal halides are soluble in water and dilute hydrochloric acid....
Group I Cations A INTRODUCTION Most metal halides are soluble in water and dilute hydrochloric acid. The exceptions are silver ion, Ag mercurous ion, Hg,: and lead(II) ion, Pb. Consequently, the addition of HCI to a solution of metal cations leads to the selective precipitation of these three ions. While the theory behind the separation and identification of these ions has been outlined in the general discus- sion of the qualitative analysis scheme, some aspects of this chemistry need to...
1) You need to make an aqueous solution of 0.209 M potassium fluoride for an experiment...
1) You need to make an aqueous solution of 0.209 M potassium fluoride for an experiment in lab, using a 300 mL volumetric flask. How much solid potassium fluoride should you add? grams 2)How many milliliters of an aqueous solution of 0.244 M zinc acetate is needed to obtain 11.1 grams of the salt? mL 3) In the laboratory you dissolve 13.9 g of copper(II) chloride in a volumetric flask and add water to a total volume of 125 ....
all 5&6
5.) Solid silver bromide , AgBr, can be dissolved by adding concentrated aqueous ammonia to give the water- soluble silver-ammonia complex ion. AgBr(s) + 2NH,(aq) U Ag(NH), (aq) + Br(aq) (a) Show that this equation is the sum of two other equations, one representing the dissolution of AgBr into its component ions and the other representing the formation of the silver-ammonium complex from silver ion and ammonia (b) Calculate the equilibrium constant for the above reaction K,(AgBr) =...
2. With the precipitate (AgCl) still present in the test tube, add aqueous ammonia. The precipitate should disappear. This means that silver chloride is soluble in ammonia solution. It is soluble because silver ion and ammonia form a complex called diamminesilver (I) chloride, [Ag(NH3)2]Cl which in solution exists as [Ag(NH)2]* and Cl ions. You could have guessed that this would have happened if you looked over the Table A values of Kr at the end of this lab (and you...
[24]Following questions are based on Experiment #17 "General ation unknown analysis The data and results provided pertain to a specific unknown analysis. Provide Answers to the following for this analysis 1 (a) To separate Qualitative Analytical (QA) Group I from the other groups tested in the general cation unknown you must add (b) The precipitate obtained in (a) above was centrifuged and the supernatant liquid decanted. The The warm test tube contained no precipitate. Based on this observation, provide the...
Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below, remember phases. Aluminum is more likely to form a hydrated complex than the other four ions remaining in solution, because of its relatively small size and high charge To separate the Group B2 ion, the solution first is made basic by adding ammonia. In the presence of this weak base the pH is adjusted to 9-10 and the group B ions form insoluble hydroxides....
The precipitate did not dissolve because sulfate ion is too weak a base. The amount of sulfate ion that reacts with the hydronium ion is too small to cause a shift in the equilibrium sufficient to dissolve a signiticant amount of the insoluble sulfate. In general, the anion of a precipitate must be a stronger base than fluoride ion in order for the precipitate to be dissolved by the addition of a strong acid. After the reactions with barium ion,...
Oxalate ion will interfere with the Group D tests after we make the solution acidic. Also, ammonium ion may prevent the precipitation of Group Dcations as hydroxides in sodium hydroxide solution. Thus, must treat the supernatant liquid left after we have precipitated calcium oxalate, in order to destroy any remaining Oxalate or ammonium ions prior to further analysis. To accomplish this, we transfer the solution to a crucible, add concentrated nitric acid and heat the mixture to dryness in a...
2. How are the Group I cations first precipitated from solution? 3. Write the net-ionic equation for the initial precipitation of any one Group I cation from your unknown solution. 4. Lead(II) chromate is used as a yellow pigment in paints. Write the net-ionic equation for its formation in this Experiment during the confirmatory test for lead(II). 5. When ammonia is added to a white precipitate of mercury(I) chloride, the precipitate turns grayish-black. Write the net-ionic equation for what happens,...
Group 1 Flowchart Use the following chemical facts to construct a flow chart for this lab: 1 Group 1 cations are Ag, Hg, and Pb 2. AgH a and Pbare given to you in lab as their nitrates which are soluble in water (denoted by as) 3 AgHgand Pb are the only common ions that form a precipitate (denoted by with the Cl ion, presented as Hcl They all form white precipitates. 4. These Group 1 precipitates are separated from...
Group I Cations A INTRODUCTION Most metal halides are soluble in water and dilute hydrochloric acid. The exceptions are silver ion, Ag mercurous ion, Hg,: and lead(II) ion, Pb. Consequently, the addition of HCI to a solution of metal cations leads to the selective precipitation of these three ions. While the theory behind the separation and identification of these ions has been outlined in the general discus- sion of the qualitative analysis scheme, some aspects of this chemistry need to...
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