A 50 kg drug user dissolves 1g of ketamine in one cup of water (236.5ml). The purity of the ketamine is only 25%, therefore the user actually used 0.25g of ketamine Calculate the volume of the ketamine solution the user would need to inject to experience a high (if the high is reached at .05mg/kg)
The high is reached at .05mg/kg. This means that for a person of 1kg weight, 0.05mg drug is needed to experience a high.
Therefore, for a person of 50kg, 2.5mg drug will be needed to get high.
Now, 0.25 g drug is present in 236.5 ml water.
So, 1g =1000mg drug will be present in 236.5÷0.25 = 946 ml
And, 2.5 mg drug will be present in (946 × 2.5) ÷1000 ml
= 2.365 ml
Hence, a person need only 2.365 ml solution to get high.
A 50 kg drug user dissolves 1g of ketamine in one cup of water (236.5ml). The...
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YOU ONLY NEED TO ANSWER QUESTIONS 1,5, & 8
AND…in addition to answering each question, state 2 other
questions after each of these that might be asked of you by a
health professional that would call on you to do the same
calculation, or know the same concept. Give answer for these, and
show all work.
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Additional info:
Meal = 1720 Kilocalories
Mass of myself = 50 kg
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I need help answering the rest of these.
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average molar mass?
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