Write an SOP for the preparation of mM solution of clotrimazole (mw: 344.8) starting with a 10 mM stock solution.
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Write an SOP for the preparation of mM solution of clotrimazole (mw: 344.8) starting with a...
Indicate the appropriate protocol below to prepare the required solution A) Solution 1 Preparation: Prepare: 1 liter of 2 Molar Tris From: solid Tris, MW = 121.1 g/mol Procedure: B) Solution 2 Preparation: Prepare: 1 liter of 0.01 mg/mL ascorbic acid From: solid ascorbic acid , MW = 176.1 g/mol Procedure: C) Solution 3 Preparation: Prepare: 1 liter of 100 mM Tris From: 1 Molar Tris stock solution Procedure: D) Solution 4 Preparation: Prepare: 1 liter of 50 mM CaCl2...
10. From a 3.01 mg/mL stock solution of ONPG (MW 301.25), prepare 1000 ML of a 1.0 mM ONPG solution. How much stock and how much water are needed to make this solution? Show your work. Be sure to include proper units!
1) Solution Components A 1 mL 100 mM NaH2PO4 + 9 mL 100 mM Na2HPO4 B 5 mL 100 mM NaH2PO4 + 5 mL 100 mM Na2HPO4 C 9 mL 100 mM NaH2PO4 + 1 mL 100 mM Na2HPO4 D 10 mL 100 mM NaH2PO4 stock solution E 10 mL 100 mM Na2HPO4 stock solution F 10 mL distilled water pKa of phosphate: 6.8 How would you calculate the pH of each equation using the Henderson Hasselbalch equations? 2) Tris...
Starting with a stock solution of 4 mM KMnO4, you plan to make 16 mL of each of the following concentrations of KMnO4: 1.0 mM, 250 μM, 62.5 μM , and 15.6 μM. What is the V1, expressed in mL, for this dilution series? Report your answer to 2 decimal places.
Solution Preparation Calculations There are three solutions that need to be made. Be sure to have the calculations for all three of these solutions. Since these volumes are enough for the entire lab, I will assign lab groups to make different solutions (but calculations for all solutions need to be in your lab notebook). On the "Observations" side of the protocol, state who is preparing the solution. Solution 1 (Buffer) 0.1 M Sodium phosphate buffer, pH 6.8. Prepare 500 ml....
Question: Starting with a 100,000 ug/mL manganese
stock solution, write out a dilution scheme for the preparation
100mL each of 0.5, 1.0, and 2.0 mg/L calibration standards.
Note: My original scheme was to do the following,
however this is not the most efficient scheme. The amount of stock
solution that should be used is 50mL, not 100mL as shown in my
calculation.
but noo'ol = 741 Gr cealal 1 (10,000 mg/L) (V.) = (0.1L) (100 mg) V, 0.4 (100 mgle)...
The preparation of an aqueous solution is described in the table below. For this solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the other row....
The preparation of an aqueous solution is described in the table
below. For this solution, write the chemical formulas of the
major species present at
equilibrium. You can leave out water itself.
Write the chemical formulas of the species that will act as
acids in the 'acids' row, the formulas of the species that will act
as bases in the 'bases' row, and the formulas of the species that
will act as neither acids nor bases in the 'other' row....
The preparation of an aqueous solution is described in the table
below. For this solution, write the chemical formulas of the
major species present at
equilibrium. You can leave out water itself.
Write the chemical formulas of the species that will act as
acids in the 'acids' row, the formulas of the species that will act
as bases in the 'bases' row, and the formulas of the species that
will act as neither acids nor bases in the 'other' row....
You are given a 2.8 mM solution of a protein (MW 27,000 g/mol). Using this information fill in the blanks below to fit the units given. ___________________μmole/ml ___________________ g/L ___________________ mg/ml Convert 46.2 nmol/ml to μM. Convert 46.2 μmol/L to μM. Convert 46.2 nmol/μL to μM.