Question

What is the volume occupied by 0.247 mol of helium gas at 1.27 atm and 308 K ?

Answer 1

Using ideal gas equation, PV = nRT

P = 1.27 atm

n = 0.247 mole

T = 308 K

R = 0.082

So, Volume = V = (nRT) /P = 4.91 L

So, volume = 4.91 L

Do rate if you understand