What is the volume occupied by 0.251 mol of helium gas at 1.35 atm and 307 K ?
Given:
P = 1.35 atm
n = 0.251 mol
T = 307 K
use:
P * V = n*R*T
1.35 atm * V = 0.251 mol* 0.08206 atm.L/mol.K * 307 K
V = 4.6839 L
Answer: 4.68 L
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