Solution:
1) HCOOH = CO2 + H2
The oxidation number of carbon in HCOOH is +2 and in CO2, it is +4.
HCOOH (+2) ===== CO2 (+4)
Hence, number of electron transfered = 4 - 2 = 2
Therefore, process is oxidation.
2) HCOOH + H2O ===== CH3OH + O2
The oxidation number of C in HCOOH is +2 and -2 in CH3OH
Therefore,
HCOOH ( +2) ===== CH3OH (-2)
Thus,
Number of electron transfered = -2 - (+2) = -4
Hence, 4 electrons are transfered and procwss in reduction.
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