Does a positive s’ value correspond to a real or a virtual image? Does a positive...
Does a positive s’ value correspond to a real or a virtual image? Does a positive s’ value correspond to an image to the left or to the right of the lens?
• Does a negative s’ value correspond to a real or a virtual image? Does a negative s’ value correspond to an image to the left or to the right of the lens?
• Which kind of image (real or virtual) appears to the right of the lens? Which kind of image (real or virtual) appears to the left of the lens?
• Which kind of lens (converging/diverging) creates real images? Which kinds of lenses (converging/diverging) create virtual images?
• Does a positive value for M correspond to an upright or an inverted image? What about a negative M value?
Homework Answers
According to cartesian sign convention- (Remind it )
- positive value of s' represents the image is real. also to the right of the lens ( if object is left side ).
- negative value of s' represents the image is virtual , also to the left side (if object is left side )
- IF object is left side then right side image is real and left side image is virtual .
- converging lens creates Real and virtual image for real image it is converging lens. diverging lens always creates virtual image.
- positive value of the magnification m represents the image is upright . and negative value of m represents the image is inverted.
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Could you please show all of the steps taken in solving the
problem and explain the process fully, using sentences/phrases (if
possible) to understand why those steps were taken and
why you got that answer.
Also could you please draw a diagram with any applicable
variables/values to help visualize the problem better.
Thank you in advance for all the help!
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