Question

Be sure to answer all parts. Describe the hybridization state of Se in SeF6 by completing the orbital diagram of Se in its excited state. In the diagrams below, ↑ represents an electron with spin +1/2, and ↓ represents an electron with spin −1/2.    4d5 ↑    ↑    ↑    ↑    ↑ 3d10 ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ 4s1 ↑ 3p6 ↑ ↓ ↑ ↓ ↑ ↓ 3s2 ↑ ↓ 2p6 ↑ ↓ ↑ ↓ ↑ ↓ 2s2 ↑ ↓ 1s2 ↑ ↓    4p4 ↑ ↓ ↑    ↑ 3d10 ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ 4s2 ↑ ↓ 3p6 ↑ ↓ ↑ ↓ ↑ ↓ 3s2 ↑ ↓ 2p6 ↑ ↓ ↑ ↓ ↑ ↓ 2s2 ↑ ↓ 1s2 ↑ ↓    4d3 ↑    ↑    ↑ 4p3 ↑    ↑    ↑ 3d10 ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ 4s2 ↑ ↓ 3p6 ↑ ↓ ↑ ↓ ↑ ↓ 3s2 ↑ ↓ 2p6 ↑ ↓ ↑ ↓ ↑ ↓ 2s2 ↑ ↓ 1s2 ↑ ↓    4d2 ↑    ↑ 4p3 ↑    ↑    ↑ 3d10 ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ 4s1 ↑ 3p6 ↑ ↓ ↑ ↓ ↑ ↓ 3s2 ↑ ↓ 2p6 ↑ ↓ ↑ ↓ ↑ ↓ 2s2 ↑ ↓ 1s2 ↑ ↓    The 3s, 3p, and 3d shells combine to make a hybrid orbital.    The 3s, 3p, and 4d shells combine to make a hybrid orbital.    The 4s, 4p, and 3d shells combine to make a hybrid orbital.    The 4s, 4p, and 4d shells combine to make a hybrid orbital.

Answer 1