Given the bsg_planets table created by using the following
definition query :
--
CREATE TABLE `bsg_planets` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
`population` bigint(20) DEFAULT NULL,
`language` varchar(255) DEFAULT NULL,
`capital` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
Insert information about the planet Mars which has a population of
2, language as "Binary" and "Olympus Mons" as Capital,
in bsg_planets. Then list the row(s), with all the information for
that planet.
Please find the iNSERT query below.
QUERY
INSERT INTO bsg_planets VALUES ('Mars', 2, 'Binary', 'Olympus Mons');
SELECT * FROM bsg_planets WHERE name = 'Mars';
Given the bsg_planets table created by using the following definition query : -- CREATE TABLE `bsg_planets`...
Using SQL and the following info Question 3: Find the people who do not have Viper Certification but are still assigned to Viper class ship Find the fname, lname, and ship_instance_id for all people who do not have Viper certification but are assigned to at least one instance of a Viper class ship (this includes all variants of Viper class ships). Return a row for every ship/person combination. Order your results by fname in ascending order. Use the BSG database...
Using SQL and the following info Question 3: Find the people who do not have Viper Certification but are still assigned to Viper class ship Find the fname, lname, and ship_instance_id for all people who do not have Viper certification but are assigned to at least one instance of a Viper class ship (this includes all variants of Viper class ships). Return a row for every ship/person combination. Order your results by fname in ascending order. Use the BSG database...
-- Create a table with the following columns, named bsg_spaceship -- -- id - an auto-incrementing integer which is also the primary key -- name - variable-length string with a max of 255 characters, cannot be null -- separate_saucer_section - a boolean property which specifies whether or not there is a separate saucer section on the spaceship. This defaults to No. -- length - integer, cannot be null -- -- Once you have created the table, run the query "DESCRIBE...
Consider the table actor which already exists in our database, with 200 rows. Upon executing SHOW CREATE TABLE `actor`, we get the following: CREATE TABLE `actor` ( `actor_id` smallint(5) unsigned NOT NULL AUTO_INCREMENT, `first_name` varchar(10) NOT NULL, `last_name` varchar(10) NOT NULL, `last_update` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, PRIMARY KEY (`actor_id`), KEY `idx_actor_last_name` (`last_name`) ) ENGINE=InnoDB AUTO_INCREMENT=201 DEFAULT CHARSET=utf8 You will need this table for any questions below which refer to an `actor` table. 1. Using the actor...
These question is for mysql, so I want know what is answer
that is information for source:
DROP DATABASE IF EXISTS travel;
CREATE DATABASE travel;
USE travel;
--
-- Table structure for table `equipment`
--
DROP TABLE IF EXISTS `equipment`;
/*!40101 SET @saved_cs_client = @@character_set_client */;
/*!40101 SET character_set_client = utf8 */;
CREATE TABLE `equipment` (
`EquipID` int(11) NOT NULL DEFAULT '0',
`EquipmentName` varchar(50) NOT NULL DEFAULT '',
`EquipmentDescription` varchar(100) NOT NULL DEFAULT '',
`EquipmentCapacity` int(11) NOT NULL DEFAULT '0',...
CREATE TABLE Gender ( gender CHAR(1), description VARCHAR(10), PRIMARY KEY (gender) ); CREATE TABLE People ( ID INT, name VARCHAR(50), gender CHAR(1), height FLOAT, PRIMARY KEY (ID), FOREIGN KEY (gender) REFERENCES Gender (gender) ); CREATE TABLE Sports ( ID INT, name VARCHAR(50), record FLOAT, PRIMARY KEY (ID), UNIQUE (name) ); CREATE TABLE Competitions ( ID INT, place VARCHAR(50), held DATE, PRIMARY KEY (ID) ); CREATE TABLE Results ( peopleID INT NOT NULL, competitionID INT NOT NULL, sportID INT NOT NULL,...
Query the apartment table and find nearby restaurants with in 200 meters distance. I have two tables one gives the home adressses and second has near by businesses with latitude and longitude given. I need to find restaurants nearby the adress with in 200 meters. Each business also has longitude/latitude information, we can get the database to calculate distances to various useful points close by to each apartment. So we have two tables 1. Apartments and no 2 is business....
5. 2. Challenge Defining the reference table A mysql prompt has been opened for you. Using the college database, complete the following tasks (use either a single-line or a multi-line SQL statement): Create a courses table with this definition (try using a multi-line SQL statement): +---------+---------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+---------------------+------+-----+---------+----------------+ | id | int(3) unsigned | NO | PRI | NULL | auto_increment | | title | varchar(255) | NO...
stuck on creating view Use a SQL statement to create a view vIBM_MMM (year, month, IBM_price, MMM_price) that contains the year and month, average close prices of IBM and MMM for the year/month. Your view should directly access the Historial_price table to have the latest data. mysql> desc Historical_prices; +-----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+----------------+ | id | bigint(20) | NO | PRI | NULL | auto_increment | | symbol |...
Create a classrooms table with this definition (try using a multi-line SQL statement): +-----------+-----------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+-----------------+------+-----+---------+----------------+ | id | int(3) unsigned | NO | PRI | NULL | auto_increment | | room_num | int(4) unsigned | NO | UNI | NULL | | | course_id | int(3) unsigned | YES | MUL | NULL | | +-----------+-----------------+------+-----+---------+----------------+