what is the kinetic energy in joules of a 46 gram object traveling at 4.7 m/s?

Question

Question

science physics

Answer 1

Answer #1

Answer 2

Similar Homework Help Questions

Kinetic Energy- KE-1 a) A 1,500kg car is traveling at 30.0m/s. How many joules of kinetic...

Kinetic Energy- KE-1 a) A 1,500kg car is traveling at 30.0m/s. How many joules of kinetic enorekye energy as the KE-2 a) Two objects with masses m -20.0 have? does the car b) Find the speed in km/hr for a 7.00kg bowling ball to have the same etic energy Find the ratio E/Ex g and my-60.0kg are both traveling with the same speed V. b) Two objects with identical masses m are traveling with speeds V1 20.0m's c) In part...
How fast (to within 20%) would an object have to be traveling for its kinetic energy...

How fast (to within 20%) would an object have to be traveling for its kinetic energy per gram to be the same as the chemical energy density of gasoline (10 Cal/g) ? (a) 1 m s-1 (b) 100 km s-1 (c) 10 km s-1 (d) 1000 m s-1 Please explain why. Thank you!
In travelling a distance of 0.5m, an object gained 200 Joules of kinetic energy. What work...

In travelling a distance of 0.5m, an object gained 200 Joules of kinetic energy. What work was done on the object, assuming no frictional forces acted? What was the average forces acting on the object? If a force of 600N had acted over the same distance, what would have been the gain in kinetic energy?

(a) What is the kinetic energy in joules of a 960-kg automobile traveling at 76 km/h?...

(a) What is the kinetic energy in joules of a 960-kg automobile traveling at 76 km/h? J (b) How much work would have to be done to bring a 960-kg automobile traveling at 76 km/h to a stop? J
(a) What is the kinetic energy in joules of a 1120-kg automobile traveling at 78 km/h?...

(a) What is the kinetic energy in joules of a 1120-kg automobile traveling at 78 km/h? J (b) How much work would have to be done to bring a 1120-kg automobile traveling at 78 km/h to a stop? J
1. How much kinetic energy does an object of mass m traveling with a velocity vx...

1. How much kinetic energy does an object of mass m traveling with a velocity vx in the x-direction have? 2. How much kinetic energy does an object of mass m traveling with a velocity ~v = vx ˆi + vy ˆj have? 3. Since the pythagorean theorem states that v ^2 = v ^2 x + v ^2 y , we can write the kinetic energy as K = 1/2mv^2 x + 1/2mv^2 y . Does this mean that...

An 4.7-kg object moving at 12.2 m/s catches up and collides with an 22.3-kg object moving...

An 4.7-kg object moving at 12.2 m/s catches up and collides with an 22.3-kg object moving at 2.1 m/s in the same direction. After the collision the 4.7-kg object is observed to be moving in the opposite direction with the speed of 2.6 m/s. How much kinetic energy was lost in this system?
Q) What is the kinetic energy, in joules, of a molecule of oxygen moving at a...

Q) What is the kinetic energy, in joules, of a molecule of oxygen moving at a speed of 255 m/s(use the appropriate prefix to avoid exponential notation) a) The equation for kinetic energy is ½mv2, and is in units of joules. What are the component units for joules in terms of mass and velocity? kg m^2/s^2 b) From the previous part, we know that the mass needs to be in units of kg. What is the mass of an oxygen...
An object is traveling such that it has a momentum of magnitude 22.7 kg · m/s...

An object is traveling such that it has a momentum of magnitude 22.7 kg · m/s and a kinetic energy of 300 J. Determine the following. (a)speed of the object in meters per second m/s (b)mass of the object in kilograms kg

1) the kinetic energy of a 15.2 kg object traveling at 8.49 m/s is ___ J....

1) the kinetic energy of a 15.2 kg object traveling at 8.49 m/s is ___ J. 2) A 437.2 g sample of an unknown substance requires 8460 J to increase its temperature from 19.3 oC to 68.9 oC. The specific heat of the substance is ___ J/g oC. 3) A 437.2 g sample of an unknown substance requires 8460 J to increase its temperature from 19.3 oC to 68.9 oC. According to table 5.1 in the text, the sample may...