A wire carries a current of 7.0 A in a direction that makes an
angle of 37.0° with the direction of a magnetic field of strength
0.100 T. Find the magnetic force on a 3.00 m length of the
wire.
N
Solution)
Given,
Current, i=7.0A
magnetic field strength B=0.100T
angle between i and B, theta=37 degree
length of the wire , l=3.00m
Now, we know
magnetic force F=BIL*sin(theta)
=0.100*7.0*3*sin37
=1.263 N (Ans)
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