What would be the final temperature if 8.94 x 10^3 joules of heat were added to...
What would be the final temperature if 8.94 x 10^3 joules of heat were added to 454 grams of copper, specific heat 0.386 J/g0C, at 23.00C?
Homework Answers
Let the final Temperature be T
Heat added = mass * specific heat capacity of copper * Change in temperature
8.94 * 10^3 = 454 * 0.386 * (T-23.00)
(T-23.00) = 51.01
T = 23.00 + 51.01 = 74.01
Hence the final temperature will be equal to 74.01 Celsius
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