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5000 Joules of heat are added to 100 grams of water at 30 Celsius. Calculate the...

5000 Joules of heat are added to 100 grams of water at 30 Celsius. Calculate the final temperature. Cpwater = 4.184 J/g C

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Answer #1

Answer:

We know that heat q=mCp(Tf-Ti)

Where q= heat, m=mass, Cp=specific heat, Ti=initial temperature and Tf=final temperature.

Given q=5000J, m=100g, Cp=4.184 J/g°C, Ti=30°C, Tf=?

Tf-Ti=q/mCp

Tf=Ti+(q/mCp)

Tf=30°C + (5000 J/100 g x 4.184 J/g°C)

Tf=30°C + 11.95 °C

Tf=41.95 °C

Thanks and I hope you like it.

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