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if mass m1=0.02 kg is at (0,0) mass m2=0.03 kg is at (3,0) mass m3=0.04 kg...

if mass m1=0.02 kg is at (0,0)
mass m2=0.03 kg is at (3,0)
mass m3=0.04 kg is at (2,2)
what is the center of mass?
0 0
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Answer #1

x-component of COM = m1x1 + m2x2 + m3x3 / m1 + m2 + m3

= 0.02*0 + 0.03*3 + 0.04*2 / 0.02 + 0.03 + 0.04

= 1.89

y-component of COM = m1y1 + m2y2 + m3y3 / m1 + m2 + m3

= 0.02*0 + 0.03*0 + 0.04*2 / 0.02 + 0.03 + 0.04

= 0.89

so COM is at (1.89,0.89)

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