Question

It has been established for a long time that height has a positive correlation with weight....

  1. It has been established for a long time that height has a positive correlation with weight. As people gets taller their weight increases. In a research study, a linear regression model was proposed to predict weight based on height. R output below provides the analysis. Interpret it, list any strengths and limitations of the result.

Call:

lm(formula = Weight ~ Height)

Residuals:

    Min      1Q Median      3Q     Max

-6.7104 -2.9217 0.4276 2.3973 7.8586

Coefficients:

            Estimate Std. Error t value Pr(>|t|)  

(Intercept) 44.4545    18.7277   2.374 0.02894 *

Age              1.3310       0.5849 2.276 0.02257 *

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 4.195 on 18 degrees of freedom

Multiple R-squared: 0.5344,    Adjusted R-squared: 0.503

F-statistic: 13.82 on 1 and 18 DF, p-value: 0.01574

0 0
Add a comment Improve this question Transcribed image text
Answer #1

As the result shows the correlation is 0.5344,

So we can say weight are height are positively correlated and the correlation of determination is 0.503, by that we can say only 50.3% of variablity of weight is explained by the regression line.

We take significance level is 0.05,

We can say that all the height and weight are significantly related. As p-value <0.05

Add a comment
Know the answer?
Add Answer to:
It has been established for a long time that height has a positive correlation with weight....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • What are the implications of predictability results in Part 2 and 3 for investment decisions? Part...

    What are the implications of predictability results in Part 2 and 3 for investment decisions? Part 2 use log dividend-price ratio to predict the 5-year stock market excess log returns: lm(formula = lnexret[2:t] ~ dp[1:t - 1]) Residuals:      Min 1Q Median 3Q Max -0.54389 -0.07305 0.01977 0.10712 0.34107 Coefficients:             Estimate Std. Error t value (Intercept) 0.58469 0.12768 4.579 dp[1:t - 1] 0.13510 0.03771 3.582                  Pr(>|t|)     (Intercept) 1.58e-05 *** dp[1:t - 1] 0.000567 *** --- Signif. codes:   0 ‘***’ 0.001 ‘**’...

  • > summaryCls) Call: Lm(formula y X) Residuals: -0.20283 -0.146910.02255 0.06655 0.44541 Coefficients: (Intercept) 0.36510 0.09904 3.686...

    > summaryCls) Call: Lm(formula y X) Residuals: -0.20283 -0.146910.02255 0.06655 0.44541 Coefficients: (Intercept) 0.36510 0.09904 3.686 0.003586 ** Min 1Q Median 3Q Max Estimate Std. Error t value Pr(>ltl) 0.96683 0.18292 5.286 0.000258*** Signif. codes: 00.001*0.010.050.11 Residual standard error: 0.1932 on 11 degrees of freedom Multiple R-squared 0.7175, Adjusted R-squared: 0.6918 F-statistic: 27.94 on 1 and 11 DF, p-value: 0.0002581 > anovaCls) Analysis of Variance Table Response : y Df Sum Sq Mean Sq F value PrOF) 1 1.04275 1.04275...

  • Using R output provided 1). Perform hypothesis testing for B(beta)1=2 using A(alpha)=0.05 > summary(ls) Call: Residuals:...

    Using R output provided 1). Perform hypothesis testing for B(beta)1=2 using A(alpha)=0.05 > summary(ls) Call: Residuals: Min 1Q Median 3Q Max 0.20283 -0.14691 -0.02255 0.06655 0.44541 Coefficients: (Intercept) 0.365100.099043.686 0.003586 ** Signif. codes: 0 '***' 0.001 '0.01 '*'0.05 '.' 0.1''1 Estimate Std. Error t value Pr>Itl) 0.96683 0.18292 5.286 0.000258** Residual standard error: 0.1932 on 11 degrees of freedom Multiple R-squared 0.7175, Adjusted R-squared: 0.6918 F-statistic: 27.94 on 1 and 11 DF, p-value: 0.0002581 anovaCLs) Analysis of Variance Table Response:...

  • How do I interpret the p-values in terms of rejecting or failing to reject H0 at...

    How do I interpret the p-values in terms of rejecting or failing to reject H0 at a 95% confidence level? What does the intercept column mean in terms of p-value? How does the p-value of the F test compare and what does it mean? In the simple linear regression I'd conclude age isn't related to pulmonary disease (what does intercept p-value mean) but for the multiple regression I'd say age and height aren't related to pulmonary disease but smoking is...

  • Call: lm(formula = launch_speed ~ launch_angle, data = muncy) Residuals:     Min      1Q Median      3Q     Max...

    Call: lm(formula = launch_speed ~ launch_angle, data = muncy) Residuals:     Min      1Q Median      3Q     Max -64.802 -9.009   2.401 10.821 20.709 Coefficients:              Estimate Std. Error t value Pr(>|t|)    (Intercept) 86.95164    0.78064 111.385 < 2e-16 *** launch_angle 0.20804    0.02865   7.261 1.77e-12 *** --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 Residual standard error: 13.74 on 438 degrees of freedom Multiple R-squared: 0.1074, Adjusted R-squared: 0.1054 F-statistic: 52.72 on 1 and 438 DF, p-value:...

  • Regression Analysis Question: is there any relationship between the economic growth rate(GDP) and unemployment rate(Unemp_Rates), Poverty...

    Regression Analysis Question: is there any relationship between the economic growth rate(GDP) and unemployment rate(Unemp_Rates), Poverty (Poverty_Rates), Technological and science workforce(ech_Scien_Wforce), high school graduate (HS_Grad_Rates) , and housing cost( Housing_Cost) This is a regression analysis result : Call: lm(formula = GDP_Rate ~ Unemp_Rates + Poverty_Rates + Tech_Scien_Wforce + HS_Grad_Rates + Housing_Cost) Residuals: Min 1Q Median 3Q Max -1.5562 -0.3988 -0.1126 0.4971 1.6748 Coefficients: Estimate Std. Error t value Pr(>|t|)    (Intercept) 15.822486 5.424619 2.917 0.00555 ** Unemp_Rates -0.053450 0.136427 -0.392...

  • Pulmonary Disease Note: You do not actually have to run analyses to answer these questions. Just...

    Pulmonary Disease Note: You do not actually have to run analyses to answer these questions. Just interpret the coefficients reported. The Data Set FEV.DAT on the Companion Website contains pulmonary function measures on 654 children ages 3-19 seen in East Boston, MA as part of Childhood Respiratory Disease (CRD) Study. The dataset contains data on age, sex, height (inches), FEV=volume (liters) of air expelled in 1 second, and smoking status. We first ran a regression of FEV on smoking shown...

  • please show your explanation thanks! ## ## Call: ## Im(formula = mpg ~ disp + hp...

    please show your explanation thanks! ## ## Call: ## Im(formula = mpg ~ disp + hp + wt + osec, data = mtcars.train.df) ## ## Residuals: Min 1Q Median ## -4.3442 -1.1687 -0.4033 3Q Max 1.0519 5.9623 ## ## Coefficients: Estimate Std. Error t value Pr>t) ## (Intercept) 31.204891 10.909916 2.860 0.00967 ** ## disp 0.009432 0.012308 0.766 0.45245 ## hp -0.032908 0.025528 -1.289 0.21208 ## wt -4.978374 1.434757 -3.470 0.00242 ** ## qsec 0.434043 0.576267 0.753 0.46011 ## ---...

  • 2.-Interpret the following regression model Call: lm(formula = Sale.Price ~ Lot.Size + Square.Feet + Num.Baths + API.2011 + dis_coast + I(dis_fwy * dis_down * dis_coast) + Pool, data = Train...

    2.-Interpret the following regression model Call: lm(formula = Sale.Price ~ Lot.Size + Square.Feet + Num.Baths + API.2011 + dis_coast + I(dis_fwy * dis_down * dis_coast) + Pool, data = Training) Residuals: Min 1Q Median 3Q Max -920838 -84637 -19943 68311 745239 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -7.375e+05 7.138e+04 -10.332 < 2e-16 *** Lot.Size -5.217e-01 1.139e-01 -4.581 5.34e-06 *** Square.Feet 1.124e+02 1.086e+01 10.349 < 2e-16 *** Num.Baths 3.063e+04 9.635e+03 3.179 0.00153 ** API.2011 1.246e+03 8.650e+01 14.405 < 2e-16...

  • Consider the dataset in the proj2-3.txt file on BlackBoard. In this problem, focus is on high systolic blood pressure (sbp) and possible explanatory variables Body Mass Index (bmi), and scale (scl)....

    Consider the dataset in the proj2-3.txt file on BlackBoard. In this problem, focus is on high systolic blood pressure (sbp) and possible explanatory variables Body Mass Index (bmi), and scale (scl). Consider the linear regression model with response high SBP and scale as explana- tory variables. Explain the coefficients in the model? Explain the null hypotheses that the estimated slope equals 0? Write a summary of your findings. What is your conclusion? Residuals: Min 1Q Median 3Q Max -72.64 -27.55...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT