What are the implications of predictability results in Part 2 and 3 for investment decisions?
Part 2
use log dividend-price ratio to predict the 5-year stock market excess log returns:
lm(formula = lnexret[2:t] ~ dp[1:t - 1])
Residuals:
Min 1Q Median 3Q Max
-0.54389 -0.07305 0.01977 0.10712 0.34107
Coefficients:
Estimate Std. Error t value
(Intercept) 0.58469 0.12768 4.579
dp[1:t - 1] 0.13510 0.03771 3.582
Pr(>|t|)
(Intercept) 1.58e-05 ***
dp[1:t - 1] 0.000567 ***
---
Signif. codes:
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.1626 on 85 degrees of freedom
(4 observations deleted due to missingness)
Multiple R-squared: 0.1312, Adjusted R-squared: 0.1209
F-statistic: 12.83 on 1 and 85 DF, p-value: 0.0005668
use log dividend-price ratio to predict the 5-year stock market excess simple returns
lm(formula = simexret[2:t] ~ dp[1:t - 1])
Residuals:
Min 1Q Median 3Q Max
-1.29268 -0.32420 -0.05609 0.34175 1.85945
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 2.2498 0.4400 5.113 1.93e-06 ***
dp[1:t - 1] 0.5142 0.1300 3.957 0.000157 ***
---
Signif. codes:
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.5603 on 85 degrees of freedom
(4 observations deleted due to missingness)
Multiple R-squared: 0.1555, Adjusted R-squared: 0.1456
F-statistic: 15.66 on 1 and 85 DF, p-value: 0.000157
Response: simexret[2:t]
Df Sum Sq Mean Sq F value Pr(>F)
dp[1:t - 1] 1 4.915 4.9150 15.656 0.000157 ***
Residuals 85 26.685 0.3139
---
Signif. codes:
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
> plot(x=dp[1:t-1],y=simexret[2:t])
> abline(lm(simexret[2:T]~dp[1:T-1]))
part 3:
use book-market ratio to predict the 5-year stock market excess log returns:
Call:
lm(formula = X5y_logexret[2:T] ~ bm[1:T - 1])
Residuals:
Min 1Q Median 3Q Max
-0.47132 -0.10729 0.00696 0.10708 0.37486
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 0.008525 0.042782 0.199 0.84253
bm[1:T - 1] 0.214525 0.067897 3.160 0.00219 **
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.165 on 85 degrees of freedom
(4 observations deleted due to missingness)
Multiple R-squared: 0.1051, Adjusted R-squared: 0.09457
F-statistic: 9.983 on 1 and 85 DF, p-value: 0.002189
Response: X5y_logexret[2:T]
Df Sum Sq Mean Sq F value Pr(>F)
bm[1:T - 1] 1 0.27182 0.271825 9.983 0.002189 **
Residuals 85 2.31445 0.027229
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
use book-market ratio to predict the 5-year stock market excess simple returns:
Call:
lm(formula = X5y_exret[2:T] ~ bm[1:T - 1])
Residuals:
Min 1Q Median 3Q Max
-1.04319 -0.39755 -0.06091 0.36066 1.95017
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 0.1337 0.1510 0.885 0.37843
bm[1:T - 1] 0.6822 0.2397 2.846 0.00555 **
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.5826 on 85 degrees of freedom
(4 observations deleted due to missingness)
Multiple R-squared: 0.08699, Adjusted R-squared: 0.07625
F-statistic: 8.099 on 1 and 85 DF, p-value: 0.00555
Analysis of Variance Table
Response: X5y_exret[2:T]
Df Sum Sq Mean Sq F value Pr(>F)
bm[1:T - 1] 1 2.749 2.74903 8.099 0.00555 **
Residuals 85 28.852 0.33943
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Before uploading the outcomes of R, first upload the base and details of the problem, without them just depending on the output no one can solve it. Only maximum you can expect in this case is that guessed solution which maybe right or maybe wrong.
Kindly upload the whole problem with complete details, not just R programme outputs.
What are the implications of predictability results in Part 2 and 3 for investment decisions? Part...
Using R output provided
1). Perform hypothesis testing for B(beta)1=2 using
A(alpha)=0.05
> summary(ls) Call: Residuals: Min 1Q Median 3Q Max 0.20283 -0.14691 -0.02255 0.06655 0.44541 Coefficients: (Intercept) 0.365100.099043.686 0.003586 ** Signif. codes: 0 '***' 0.001 '0.01 '*'0.05 '.' 0.1''1 Estimate Std. Error t value Pr>Itl) 0.96683 0.18292 5.286 0.000258** Residual standard error: 0.1932 on 11 degrees of freedom Multiple R-squared 0.7175, Adjusted R-squared: 0.6918 F-statistic: 27.94 on 1 and 11 DF, p-value: 0.0002581 anovaCLs) Analysis of Variance Table Response:...
> summaryCls) Call: Lm(formula y X) Residuals: -0.20283 -0.146910.02255 0.06655 0.44541 Coefficients: (Intercept) 0.36510 0.09904 3.686 0.003586 ** Min 1Q Median 3Q Max Estimate Std. Error t value Pr(>ltl) 0.96683 0.18292 5.286 0.000258*** Signif. codes: 00.001*0.010.050.11 Residual standard error: 0.1932 on 11 degrees of freedom Multiple R-squared 0.7175, Adjusted R-squared: 0.6918 F-statistic: 27.94 on 1 and 11 DF, p-value: 0.0002581 > anovaCls) Analysis of Variance Table Response : y Df Sum Sq Mean Sq F value PrOF) 1 1.04275 1.04275...
Regression Analysis Question: is there any relationship between the economic growth rate(GDP) and unemployment rate(Unemp_Rates), Poverty (Poverty_Rates), Technological and science workforce(ech_Scien_Wforce), high school graduate (HS_Grad_Rates) , and housing cost( Housing_Cost) This is a regression analysis result : Call: lm(formula = GDP_Rate ~ Unemp_Rates + Poverty_Rates + Tech_Scien_Wforce + HS_Grad_Rates + Housing_Cost) Residuals: Min 1Q Median 3Q Max -1.5562 -0.3988 -0.1126 0.4971 1.6748 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 15.822486 5.424619 2.917 0.00555 ** Unemp_Rates -0.053450 0.136427 -0.392...
It has been established for a long time that height has a positive correlation with weight. As people gets taller their weight increases. In a research study, a linear regression model was proposed to predict weight based on height. R output below provides the analysis. Interpret it, list any strengths and limitations of the result. Call: lm(formula = Weight ~ Height) Residuals: Min 1Q Median 3Q Max -6.7104 -2.9217 0.4276 2.3973 7.8586 Coefficients: Estimate Std. Error t value...
Call: lm(formula = launch_speed ~ launch_angle, data = muncy) Residuals: Min 1Q Median 3Q Max -64.802 -9.009 2.401 10.821 20.709 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 86.95164 0.78064 111.385 < 2e-16 *** launch_angle 0.20804 0.02865 7.261 1.77e-12 *** --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 Residual standard error: 13.74 on 438 degrees of freedom Multiple R-squared: 0.1074, Adjusted R-squared: 0.1054 F-statistic: 52.72 on 1 and 438 DF, p-value:...
Interpreting regression results 2. This is the result of a regression where goals is the dependent variable and minutes played is the explanatory variable. a. Write out the simple linear regression equation that predicts goals based on time played using the output displayed here. If the average soccer player played one additional game (90 minutes), how many additional goals would you predict them to have scored? b. Call: 1m(formula goalstimeplayed, data -data) Residuals: Min 1Q Median 3Q Max 5.0572-1.6294 -0.3651...
How do I interpret the p-values in terms of rejecting or failing
to reject H0 at a 95% confidence level? What does the intercept
column mean in terms of p-value? How does the p-value of the F test
compare and what does it mean? In the simple linear regression I'd
conclude age isn't related to pulmonary disease (what does
intercept p-value mean) but for the multiple regression I'd say age
and height aren't related to pulmonary disease but smoking is...
Consider the dataset in the proj2-3.txt file on BlackBoard. In this problem, focus is on high systolic blood pressure (sbp) and possible explanatory variables Body Mass Index (bmi), and scale (scl). Consider the linear regression model with response high SBP and scale as explana- tory variables. Explain the coefficients in the model? Explain the null hypotheses that the estimated slope equals 0? Write a summary of your findings. What is your conclusion? Residuals: Min 1Q Median 3Q Max -72.64 -27.55...
2.-Interpret the following regression model Call: lm(formula = Sale.Price ~ Lot.Size + Square.Feet + Num.Baths + API.2011 + dis_coast + I(dis_fwy * dis_down * dis_coast) + Pool, data = Training) Residuals: Min 1Q Median 3Q Max -920838 -84637 -19943 68311 745239 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -7.375e+05 7.138e+04 -10.332 < 2e-16 *** Lot.Size -5.217e-01 1.139e-01 -4.581 5.34e-06 *** Square.Feet 1.124e+02 1.086e+01 10.349 < 2e-16 *** Num.Baths 3.063e+04 9.635e+03 3.179 0.00153 ** API.2011 1.246e+03 8.650e+01 14.405 < 2e-16...
What is the dependent variable in this analysis? What are the independent variables in this analysis? Draw a diagram representing the model being tested. What are the assumptions which need to be met PRIOR to interpreting the results of the analysis? What do you conclude about the quality of the model? What do you conclude about each of the predictors? Interpret the coefficient for any significant predictors. ## ## Call: ## lm(formula = Ought_Score ~ Inherence_Bias + Ought_Score + educ...