Question

(8c28p70) In a Hall-effect experiment, a current of 3.1 A sent lengthwise through a conductor 1.1 cm wide, 3.6 cm long, and 12μm thick produces a transverse (across the width) Hall voltage of 8.2 μV when a magnetic field of 1.5 T is passed perpendicularly through the thickness of the conductor. From these data, find the drift velocity of the charge carriers. 4.97×10-4 m/s You are correct. Your receipt no. is 158-6556 Help: Receipt Previous Tries Find the number density of charge carriers. ( m-3)

Answer 1

You've already solved the part for drift velocity, if you need help with part please comment below.

Since we know that drift velocity is given by:

Vd = I/(N*A*e)

N = number density of charge carriers = ?

I = Current = 3.1 Amp

A = Area of Conductor = 1.1*10^-2 m*12*10^-6 m

(See that current is sent lengthwise, So cross-sectional area will be width*thickness)

e = Charge on electron = 1.6*10^-19 C

Vd = 4.97*10^-4 m/s

So,

N = I/(Vd*A*e)

N = 3.1/(4.97*10^-4*1.1*10^-2*12*10^-6*1.6*10^-19)

N = 2.95*10^29 m^-3 = Number density of charge carriers

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