For a certain chemical reaction, the standard Gibbs free energy of reaction is −141. kJ. Calculate...
For a certain chemical reaction, the standard Gibbs free energy of reaction is −141. kJ. Calculate the temperature at which the equilibrium constant K=3.6 x 10^25.
Homework Answers
The relation between Gibb's free energy and the equilibrium constant is given by the following equation :
G
= - RT lnKeq
Therefore, - 141*1000 J = - 8.314 JK-1mol-1*T*(ln 3.6*1025)
Therefore, T= 141000/8.314 K-1mol-1(ln 3.6*1025)
Therefore, T= 16959 K/58.85= 288 K
Therefore, the temperature at the given conditions is 288 K.
Thank You!
Add Answer to:
For a certain chemical reaction, the standard Gibbs free energy
of reaction is −141. kJ. Calculate...
For a certain chemical reaction, the standard Gibbs free energy of reaction is 72.4 kJ. Calculate...
For a certain chemical reaction, the standard Gibbs free energy of reaction is 72.4 kJ. Calculate the temperature at which the equilibrium constant K 2.5 × 10-14 Round your answer to the nearest degree.
For a certain chemical reaction, the standard Gibbs free energy of reaction at 10.0 °C is...
For a certain chemical reaction, the standard Gibbs free energy of reaction at 10.0 °C is 99.8 kJ. Calculate the equilibrium constant for this reaction. Round your answer to 2 significant digits. K = 0 x 5 ?
estion For a certain chemical reaction, the standard Gibbs free energy of reaction at 5.00 °C...
estion For a certain chemical reaction, the standard Gibbs free energy of reaction at 5.00 °C is 84.2 kJ . Calculate the equilibrium constant K for this reaction.
For a certain chemical reaction, the standard Gibbs free energy of reaction at 25.0 °C is...
For a certain chemical reaction, the standard Gibbs free energy of reaction at 25.0 °C is − 84.7 kJ . Calculate the equilibrium constant K for this reaction. Round your answer to 2 significant digits.
Question 2 For a certain chemical reaction, the standard Gibbs free energy of reaction at 25.0°C...
Question 2 For a certain chemical reaction, the standard Gibbs free energy of reaction at 25.0°C is 126.kJ. Calculate the equilibrium constant K for this reaction.Round your answer to 2 significant digits.
Calculate the standard change in Gibbs free energy, AGixn , for the given reaction at 25.0...
Calculate the standard change in Gibbs free energy, AGixn , for the given reaction at 25.0 °C. Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. NH,CI() = NH(aq) + Cl(aq) AGxn = -7.7 kJ/mol Determine the concentration of NH(aq) if the change in Gibbs free energy, AGrxn , for the reaction is –9.53 kJ/mol. [NH] = 0.72 Consider a general reaction enzyme A(aq) = B(aq) The AG® of the reaction is -4.880 kJ mol-....
I cannot seem to figure it out. The standard Gibbs-free energy of a system is related...
I cannot seem to figure it out.
The standard Gibbs-free energy of a system is related to its equilibrium constant through the following equation. AG = R.T.In(K) In this equation R is the gas constant, T is the temperature, and the next to AG defines the conditions as standard ambient temperature and pressure, i.e. "SATP". (Answer the following questions to three significant figures.) (a) Given an equilibrium constant of 6.28 x 10-3, what is its standard Gibbs-free energy? 4.9 12.6...
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs...
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. 3H2(g) + Fe,0,($) 2Fe(s) + 3 H,0 () AGran kJ/mol
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs...
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. 6 C1,() +2 Fe,0,(s) 4 FeC1, (s) + 30,() AGE kJ/mol
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol . Calculate Δ? for this reaction...
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol .
Calculate Δ? for this reaction at 298 K when [dihydroxyacetone
phosphate]=0.100 M and [glyceraldehyde-3-phosphate]=0.00600 M .
Thank you!
For the aqueous reaction CH2OH Н— —он SO CH-0–_0 CH -0 - 0- dihydroxyacetone phosphate = glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AGⓇ' = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate) = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00600 M AG = kJ/mol
For a certain chemical reaction, the standard Gibbs free energy of reaction is 72.4 kJ. Calculate the temperature at which the equilibrium constant K 2.5 × 10-14 Round your answer to the nearest degree.
For a certain chemical reaction, the standard Gibbs free energy of reaction at 10.0 °C is 99.8 kJ. Calculate the equilibrium constant for this reaction. Round your answer to 2 significant digits. K = 0 x 5 ?
Calculate the standard change in Gibbs free energy, AGixn , for the given reaction at 25.0 °C. Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. NH,CI() = NH(aq) + Cl(aq) AGxn = -7.7 kJ/mol Determine the concentration of NH(aq) if the change in Gibbs free energy, AGrxn , for the reaction is –9.53 kJ/mol. [NH] = 0.72 Consider a general reaction enzyme A(aq) = B(aq) The AG® of the reaction is -4.880 kJ mol-....
I cannot seem to figure it out.
The standard Gibbs-free energy of a system is related to its equilibrium constant through the following equation. AG = R.T.In(K) In this equation R is the gas constant, T is the temperature, and the next to AG defines the conditions as standard ambient temperature and pressure, i.e. "SATP". (Answer the following questions to three significant figures.) (a) Given an equilibrium constant of 6.28 x 10-3, what is its standard Gibbs-free energy? 4.9 12.6...
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. 3H2(g) + Fe,0,($) 2Fe(s) + 3 H,0 () AGran kJ/mol
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. 6 C1,() +2 Fe,0,(s) 4 FeC1, (s) + 30,() AGE kJ/mol
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol .
Calculate Δ? for this reaction at 298 K when [dihydroxyacetone
phosphate]=0.100 M and [glyceraldehyde-3-phosphate]=0.00600 M .
Thank you!
For the aqueous reaction CH2OH Н— —он SO CH-0–_0 CH -0 - 0- dihydroxyacetone phosphate = glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AGⓇ' = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate) = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00600 M AG = kJ/mol
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago