Question

do the following in Node* buildLinkedList() function

1. Build linked list of 3 nodes. 2. Ask the user for the data values in the structure. 3. Follow the example above on how to build linked list. Make sure you ask the user for the data values. 4. Return head.
in Main do the following:

1. Declare a pointer to structure of type Node. 2. Call the function buildLinkedList. 3. Display the 3 nodes data values.

Answer 1

#include <stdio.h>
#include <stdlib.h>

struct Node {
int data;
struct Node* next;
};

void printList(struct Node* iterator)
{
while (iterator!=NULL) {
printf(" %d ", iterator->data);
iterator = iterator->next;
}
}
  
struct Node* buildLinkedList()
{
struct Node* head = (struct Node*)malloc(sizeof(struct Node));
struct Node* second = (struct Node*)malloc(sizeof(struct Node));
struct Node* third = (struct Node*)malloc(sizeof(struct Node));
if(head ==NULL || second ==NULL || third ==NULL )
{
return NULL;
}
  
int i = 1;
printf("Enter %d node's data: ", i++);
scanf("%d", &head->data); // assign data in first node
head->next = second; // Link first node with second
  
printf("Enter %d node's data: ", i++);
scanf("%d", &second->data); // assign data in second node
second->next = third;
  
printf("Enter %d node's data: ", i++);
scanf("%d", &third->data); // assign data in third node
third->next = NULL;
  
return head;
  
}

int main()
{
struct Node* head = NULL;
head = buildLinkedList();
  
printList(head);
  
return 0;
}

Output:

Please give thumbs up for the solution.