A screen is placed 1.50 m behind a single slit. The central maximum in the resulting...

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A screen is placed 1.50 m behind a single slit. The central maximum in the resulting...

A screen is placed 1.50 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.80 cm wide-that is, the two first-order diffraction minima are separated by 1.80 cm.

What is the distance between the two second-order minima?

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Answer 1

Answer #1

As we know that;

Here,

D=1.5 cm

Then,

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Answer 2

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