A screen is placed 1.70 m behind a single slit. The central maximum in the resulting...
A screen is placed 1.70 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 cm wide-that is, the two first-order diffraction minima are separated by 1.40 cm.
What is the distance between the two second-order minima?
Express your answer to three significant figures.
Homework Answers
fringe width for 1st order minima
x = n L D/d
since fringe width is directly proportional to n
so
x2/ x1 = n2/n1
x2 = (n2/n1)x2
for 2nd order
x2' = 2 x2 = 2* ( 2/1) * (1.4 /2)
x2' = 2.8 cm
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