7. How many moles of Ag(s) can be produced from 100.0 grams of Fe(s) according to the following equation? Fe(s) + 3 AgNO3(aq) → 3 Ag(s) + Fe(NO3)3(aq)
So 108 g of Ag is one mole
Then 578.57 g of Ag forms = 578.57/108= 5.357 moles of Ag can be formed
7. How many moles of Ag(s) can be produced from 100.0 grams of Fe(s) according to...
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